FDS6982AS Fairchild Semiconductor, FDS6982AS Datasheet - Page 7

MOSFET N-CH DUAL 30V SO-8

FDS6982AS

Manufacturer Part Number
FDS6982AS
Description
MOSFET N-CH DUAL 30V SO-8
Manufacturer
Fairchild Semiconductor
Series
PowerTrench®r
Datasheet

Specifications of FDS6982AS

Fet Type
2 N-Channel (Dual)
Fet Feature
Logic Level Gate
Rds On (max) @ Id, Vgs
28 mOhm @ 6.3A, 10V
Drain To Source Voltage (vdss)
30V
Current - Continuous Drain (id) @ 25° C
6.3A, 8.6A
Vgs(th) (max) @ Id
3V @ 250µA
Gate Charge (qg) @ Vgs
15nC @ 10V
Input Capacitance (ciss) @ Vds
610pF @ 10V
Power - Max
900mW
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
Configuration
Dual Dual Drain
Transistor Polarity
N-Channel
Resistance Drain-source Rds (on)
0.028 Ohm @ 10 V Ohm @ Q1
Forward Transconductance Gfs (max / Min)
32 S, 19 S
Drain-source Breakdown Voltage
30 V
Gate-source Breakdown Voltage
+ /- 20 V
Continuous Drain Current
6.3 A @ Q1
Power Dissipation
2000 mW
Maximum Operating Temperature
+ 150 C
Mounting Style
SMD/SMT
Minimum Operating Temperature
- 55 C
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
FDS6982AS
FDS6982ASTR

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Typical Characteristics Q1
0.01
10
Figure 20. Maximum Safe Operating Area.
100
8
6
4
2
0
0.1
10
Figure 18. Gate Charge Characteristics.
1
0
0.1
0.001
0.01
R
I
SINGLE PULSE
R
0.1
D
DS(ON)
0.0001
θ JA
= 6.3A
1
V
T
GS
A
= 135
= 25
= 10V
LIMIT
o
o
C
C/W
3
V
D = 0.5
DS
, DRAIN-SOURCE VOLTAGE (V)
Q
0.2
1
0.1
g
, GATE CHARGE (nC)
0.05
0.02
0.001
0.01
V
DC
DS
Thermal characterization performed using the conditions described in Note 1c.
Transient thermal response will change depending on the circuit board design.
SINGLE PULSE
10s
= 10V
6
1s
Figure 22. Transient Thermal Response Curve.
100ms
15V
10ms
10
1ms
0.01
20V
9
100 µ s
100
12
0.1
t
1
, TIME (sec)
50
40
30
20
10
800
600
400
200
0
0.001
Figure 19. Capacitance Characteristics.
0
0
1
Figure 21. Single Pulse Maximum
C
rss
0.01
Power Dissipation.
V
DS
5
, DRAIN TO SOURCE VOLTAGE (V)
0.1
10
C
t
1
oss
, TIME (sec)
1
10
P(pk)
Duty Cycle, D = t
T
R
J
R
θJA
- T
100
θJA
(t) = r(t) * R
10
A
t
= 135°C/W
1
= P * R
t
C
2
iss
SINGLE PULSE
R
15
FDS6982AS Rev B1
θ JA
T
θJA
A
100
= 135°C/W
θJA
1
= 25°C
(t)
/ t
V
f = 1MHz
2
GS
1000
= 0 V
1000
20

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