S1D10605 Epson Electronics America, Inc., S1D10605 Datasheet - Page 228

• Manufacturer Part Number: S1D10605
• Description: S1d15000 Series Lcd Driver With Ram
• Manufacturer: Epson Electronics America, Inc.

Voltage tripler
By connecting capacitors C1 between CAP1+ and
CAP1-, CAP2+ and CAP2- and V
potential between V
toward negative side and outputted from the Vout termi-
nal. When a double boosting is required, disconnect the
capacitor between CAP2+ and CAP2- and short-circuit
the CAP2- and Vout terminals to obtain output boosted
to the double out of the Vout (or CAP2-) terminal.
Signals from the oscillation circuit are used in the boost-
ing circuit and it then is necessary that the oscillation
circuit is in operation.
Electric potentials by the boosting functions are given
below.
Voltage Regulator
The boosting voltage occurring at V
voltage regulator, and the V
driver voltage is output. This V
by the following equation when resistors Ra and Rb (R1,
R2 and R3) are adjusted within the range of |V
Rev. 4.6
(V
CC
(GND)
=+5V) V
V
Electric potentials of double boosting
V
SS
Electric potentials of triple boosting
DD
=–5V
V
=0V
V
OUT
SS
DD
=–5V
=3V
V
=0V
OUT
DD
SS
=2V
=–15V
-V
5
SS
SS
liquid crystal display (LCD)
5
=–10V
is boosted to the triple
voltage can be determined
SS
-Vout, the electric
OUT
is sent to the
5
| < |V
OUT
|.
EPSON
V
constant and V
adjust the V
between V
and R3 constant resistors and R2 variable resistor is
recommended for fine-adjustment of V
Setup example of resistors R1, R2 and R3: (In case of
Type 1)
When the Electronic Volume Control Function is OFF
(electronic volume control register values are
(D4,D3,D2,D1,D0)=(0,0,0,0,0)):
V
From equations
Ra
Rb
REG
5
=
R1
R2
R3
(As I
• R1 + R2 + R3 = 5M ................................
• Variable voltage range by R2 V
is the constant voltage source of the IC, and it is
R1=1.27M
R2=0.85M
R3=2.88M
( 1 + R3 + R2 – R2)
(Determined by the current passing between
V
(Determined by the LCD characteristics)
DD
R
REF
, V
To obtain V
To obtain V
V
R1 + R2
5
and V
VR I
R2 = O , V
R2 = R2, V
5
output voltage, insert a variable resistor
DD
= 0 A)
=(1+
=(1+
REG
R2 + R3 = 2.92
1.35
+I
2
and V
,
R2
REF
REF
. =
5
.
3
V
)
Rb
Ra
R3+R2- R2
–2.5
REG
and
S1D15600/601/602 Series
R1+ R2
(R1 + R2) = R3 ..................
5
· (R3+R2- R2)
) V
5
5
as shown. A combination of R1
REG
= -10 V, from equation
= -6 V, from equation
REG
4
REG
0.15 V (if V
:
= –2.55V
V
= –2.55V
+
-
REG
+I
) V
R1 .....................
REF
.......................
REG
· Rb
5
DD
5
voltage.
= –6 to –10 V
is 0 V). To
1
7–33
1
:
V
V
:
1
2
3
4
DD
5