RFD15P05 Fairchild Semiconductor, RFD15P05 Datasheet - Page 3
![MOSFET P-CH 50V 15A I-PAK](/photos/5/60/56062/dpak_369d___01_sml.jpg)
RFD15P05
Manufacturer Part Number
RFD15P05
Description
MOSFET P-CH 50V 15A I-PAK
Manufacturer
Fairchild Semiconductor
Datasheet
1.RFD15P05.pdf
(8 pages)
Specifications of RFD15P05
Fet Type
MOSFET P-Channel, Metal Oxide
Fet Feature
Standard
Rds On (max) @ Id, Vgs
150 mOhm @ 15A, 10V
Drain To Source Voltage (vdss)
50V
Current - Continuous Drain (id) @ 25° C
15A
Vgs(th) (max) @ Id
4V @ 250µA
Gate Charge (qg) @ Vgs
150nC @ 20V
Input Capacitance (ciss) @ Vds
1150pF @ 25V
Power - Max
80W
Mounting Type
Through Hole
Package / Case
IPak, TO-251, DPak, VPak (3 straight leads + tab)
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
RFD15P05
Manufacturer:
HARRIS
Quantity:
10 000
Company:
Part Number:
RFD15P05SM
Manufacturer:
INTERSIL
Quantity:
1 062
©2002 Fairchild Semiconductor Corporation
Typical Performance Curves
-100
FIGURE 1. NORMALIZED POWER DISSIPATION vs CASE
-10
1.0
0.4
-1
1.2
0.8
0.6
0.2
FIGURE 4. FORWARD BIAS SAFE OPERATING AREA
-1
0
0 0
0.01
0.1
2
1
OPERATION IN THIS
AREA MAY BE
LIMITED BY r
10
TEMPERATURE
25
-5
0.5
0.2
0.1
0.05
0.02
0.01
V
DS
, DRAIN TO SOURCE VOLTAGE (V)
T
C
50
, CASE TEMPERATURE (
DS(ON)
SINGLE PULSE
75
10
FIGURE 3. NORMALIZED MAXIMUM TRANSIENT THERMAL IMPEDANCE
-10
-4
100
125
T
T
o
C)
C
J
= MAX RATED
= 25
10
o
150
-3
C
t
100µs
1ms
10ms
100ms
DC
1
, RECTANGULAR PULSE DURATION (s)
-100
175
10
-2
FIGURE 2. MAXIMUM CONTINUOUS DRAIN CURRENT vs
-200
-100
-16
-12
-10
-8
-4
0
10
25
-5
V
V
TRANSCONDUCTANCE
MAY LIMIT CURRENT
IN THIS REGION
GS
GS
FIGURE 5. PEAK CURRENT CAPABILITY
= -20V
= -10V
CASE TEMPERATURE
10
50
-4
10
-1
T
C
10
, CASE TEMPERATURE (
NOTES:
DUTY FACTOR: D = t
PEAK T
75
-3
t, PULSE WIDTH (s)
T
FOR TEMPERATURES ABOVE 25
DERATE PEAK CURRENT
CAPABILITY AS FOLLOWS:
C
= 25
RFD15P05, RFD15P05SM, RFP15P05 Rev. B
J
= P
10
o
100
C
-2
I
DM
10
=
P
x Z
0
I 25
DM
θJC
10
125
1
/t
-1
175
---------------------
t
2
x R
1
o
C)
150
t
θJC
2
–
T C
+ T
10
150
0
C
o
10
C
1
175
10
1