FDS8926A Fairchild Semiconductor, FDS8926A Datasheet - Page 4
![MOSFET N-CH DUAL 30V 5.5A SO-8](/photos/5/42/54236/261-8-soic_sml.jpg)
FDS8926A
Manufacturer Part Number
FDS8926A
Description
MOSFET N-CH DUAL 30V 5.5A SO-8
Manufacturer
Fairchild Semiconductor
Datasheet
1.FDS8926A.pdf
(5 pages)
Specifications of FDS8926A
Fet Type
2 N-Channel (Dual)
Fet Feature
Logic Level Gate
Rds On (max) @ Id, Vgs
30 mOhm @ 5.5A, 4.5V
Drain To Source Voltage (vdss)
30V
Current - Continuous Drain (id) @ 25° C
5.5A
Vgs(th) (max) @ Id
1V @ 250µA
Gate Charge (qg) @ Vgs
28nC @ 4.5V
Input Capacitance (ciss) @ Vds
900pF @ 10V
Power - Max
900mW
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
FDS8926A
FDS8926ATR
FDS8926ATR
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
FDS8926A
Manufacturer:
Fairchild Semiconductor
Quantity:
62 869
Part Number:
FDS8926A
Manufacturer:
FSC
Quantity:
20 000
Part Number:
FDS8926A-NL
Manufacturer:
FAIRCHILD/仙童
Quantity:
20 000
Part Number:
FDS8926A_NL
Manufacturer:
FAIRCHILD/仙童
Quantity:
20 000
Typical Electrical And Thermal Characteristics
0.03
0.01
0.3
0.1
50
10
Figure 7. Gate Charge Characteristics.
Figure 9. Maximum Safe Operating Area.
3
1
5
4
3
2
1
0
0.1
0
I = 5.5A
D
R
0.005
0.002
0.001
SINGLE PULSE
0.05
0.02
0.01
JA
0.2
0.5
0.2
0.1
0.0001
V
1
=135 °C/W
T = 25°C
GS
A
= 4.5V
5
D = 0.5
V
0.5
DS
0.2
, DRAI N-SOURCE VOLTAGE (V)
Q , GATE CHARGE (nC)
0.1
g
0.05
1
10
0.02
Figure 11. Transient Thermal Response Curve.
0.001
0.01
2
Single Pulse
V
DS
15
Transient thermal response will change depending on the circuit board design.
Thermal characterization performed using the conditions described in Note 1c.
= 5V
5
10V
15V
10
20
0.01
20 30
25
50
0.1
t , TIME (sec)
1
3000
1000
500
200
30
25
20
15
10
80
30
5
0
0.01
0.1
Figure 8. Capacitance Characteristics.
Figure 10. Single Pulse Maximum Power
1
f = 1 MHz
V
GS
= 0V
V
0.1
DS
0.4
, DRAIN TO SOURCE VOLTAGE (V)
SINGLE PULSE TIME (SEC)
Dissipation.
0.5
1
P(pk)
10
1
T - T
R
Duty Cycle, D = t /t
J
R
JA
2
t
JA
1
A
(t) = r(t) * R
t
= P * R
= 135 °C/W
2
10
R
5
SINGLE PULSE
JA
JA
100
T = 25°C
1
A
(t)
=135° C/W
JA
2
10
50 100
C oss
C rss
C iss
300
FDS8926A Rev.B
30
300