ATMEGA8535-16PU Atmel, ATMEGA8535-16PU Datasheet - Page 158

IC AVR MCU 8K 16MHZ 5V 40DIP

ATMEGA8535-16PU

Manufacturer Part Number
ATMEGA8535-16PU
Description
IC AVR MCU 8K 16MHZ 5V 40DIP
Manufacturer
Atmel
Series
AVR® ATmegar

Specifications of ATMEGA8535-16PU

Core Processor
AVR
Core Size
8-Bit
Speed
16MHz
Connectivity
I²C, SPI, UART/USART
Peripherals
Brown-out Detect/Reset, POR, PWM, WDT
Number Of I /o
32
Program Memory Size
8KB (4K x 16)
Program Memory Type
FLASH
Eeprom Size
512 x 8
Ram Size
512 x 8
Voltage - Supply (vcc/vdd)
4.5 V ~ 5.5 V
Data Converters
A/D 8x10b
Oscillator Type
Internal
Operating Temperature
-40°C ~ 85°C
Package / Case
40-DIP (0.600", 15.24mm)
Processor Series
ATMEGA8x
Core
AVR8
Data Bus Width
8 bit
Data Ram Size
512 B
Interface Type
2-Wire, SPI, USART
Maximum Clock Frequency
16 MHz
Number Of Programmable I/os
32
Number Of Timers
3
Operating Supply Voltage
4.5 V to 5.5 V
Maximum Operating Temperature
+ 85 C
Mounting Style
Through Hole
3rd Party Development Tools
EWAVR, EWAVR-BL
Development Tools By Supplier
ATAVRDRAGON, ATSTK500, ATSTK600, ATAVRISP2, ATAVRONEKIT
Minimum Operating Temperature
- 40 C
On-chip Adc
10 bit, 8 Channel
A/d Inputs
8-Channel, 10-Bit
Cpu Speed
16 MIPS
Eeprom Memory
512 Bytes
Input Output
32
Interface
SPI/TWI/USART
Memory Type
Flash
Number Of Bits
8
Package Type
40-pin PDIP
Programmable Memory
8K Bytes
Timers
2-8-bit, 1-16-bit
Voltage, Range
4.5-5.5 V
Controller Family/series
AVR MEGA
No. Of I/o's
32
Eeprom Memory Size
512Byte
Ram Memory Size
512Byte
Rohs Compliant
Yes
For Use With
ATSTK600 - DEV KIT FOR AVR/AVR32770-1007 - ISP 4PORT ATMEL AVR MCU SPI/JTAGATAVRISP2 - PROGRAMMER AVR IN SYSTEMATSTK500 - PROGRAMMER AVR STARTER KIT
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
ATMEGA8535-16PU
Manufacturer:
ATMEL
Quantity:
1 500
Part Number:
ATMEGA8535-16PU
Manufacturer:
ATMEL/爱特梅尔
Quantity:
20 000
Asynchronous Operational
Range
158
ATmega8535(L)
Figure 75. Stop Bit Sampling and Next Start Bit Sampling
The same majority voting is done to the stop bit as done for the other bits in the frame. If
the stop bit is registered to have a logic 0 value, the Frame Error (FE) Flag will be set.
A new high to low transition indicating the start bit of a new frame can come right after
the last of the bits used for majority voting. For Normal Speed mode, the first low level
sample can be at point marked (A) in Figure 75. For Double Speed mode the first low
level must be delayed to (B). (C) marks a stop bit of full length. The early start bit detec-
tion influences the operational range of the Receiver.
The operational range of the Receiver is dependent on the mismatch between the
received bit rate and the internally generated baud rate. If the Transmitter is sending
frames at too fast or too slow bit rates, or the internally generated baud rate of the
Receiver does not have a similar (see Table 62) base frequency, the Receiver will not
be able to synchronize the frames to the start bit.
The following equations can be used to calculate the ratio of the incoming data rate and
internal receiver baud rate.
D
S
S
S
R
Table 62 and Table 63 list the maximum receiver baud rate error that can be tolerated.
Note that normal speed mode has higher toleration of baud rate variations.
F
M
slow
(U2X = 0)
(U2X = 1)
Sample
Sample
RxD
Sum of character size and parity size (D = 5 to 10 bit).
Samples per bit. S = 16 for Normal Speed mode and S = 8 for Double Speed
mode.
First sample number used for majority voting. S
for Double Speed mode.
Middle sample number used for majority voting. S
S
is the ratio of the slowest incoming data rate that can be accepted in relation to the
receiver baud rate. R
accepted in relation to the Receiver baud rate.
M
R
= 5 for Double Speed mode.
slow
=
------------------------------------------ -
S 1
1
1
(
D
2
+
+
D S ⋅
3
2
1
fast
)S
4
+
is the ratio of the fastest incoming data rate that can be
S
F
5
3
6
7
4
8
STOP 1
9
5
10
F
0/1
(A)
6
R
= 8 for Normal Speed and S
M
fast
0/1
= 9 for Normal Speed and
=
(B)
0/1
0/1
-----------------------------------
(
D
(
+
D
1
+
)S
2
)S
+
S
2502G–AVR–04/05
(C)
M
F
= 4

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