MC9S12DJ256 MOTOROLA [Motorola, Inc], MC9S12DJ256 Datasheet - Page 114
![no-image](/images/no-image-200.jpg)
MC9S12DJ256
Manufacturer Part Number
MC9S12DJ256
Description
MC9S12DT256 Device User Guide V03.03
Manufacturer
MOTOROLA [Motorola, Inc]
Datasheet
1.MC9S12DJ256.pdf
(130 pages)
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Part Number:
MC9S12DJ256B
Manufacturer:
NO
Quantity:
20 000
Part Number:
MC9S12DJ256BCFU
Manufacturer:
MOTOROLA/摩托罗拉
Quantity:
20 000
Part Number:
MC9S12DJ256BMFU
Manufacturer:
MOTOROLA/摩托罗拉
Quantity:
20 000
Company:
Part Number:
MC9S12DJ256CCFU
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Part Number:
MC9S12DJ256CCFU
Manufacturer:
MOTOROLA/摩托罗拉
Quantity:
20 000
Company:
Part Number:
MC9S12DJ256CCPV
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Company:
Part Number:
MC9S12DJ256CFUE
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Company:
Part Number:
MC9S12DJ256MPVE
Manufacturer:
Freescale Semiconductor
Quantity:
135
MC9S12DT256 Device User Guide — V03.03
The loop bandwidth f
typical values are 50. = 0.9 ensures a good transient response.
And finally the frequency relationship is defined as
With the above values the resistance can be calculated. The example is shown for a loop bandwidth
f
The capacitance C
The capacitance C
A.5.3.2 Jitter Information
The basic functionality of the PLL is shown in Figure A-2. With each transition of the clock f
deviation from the reference clock f
accordingly.The adjustment is done continuously with no abrupt changes in the clock output frequency.
Noise, voltage, temperature and other factors cause slight variations in the control loop resulting in a clock
jitter. This jitter affects the real minimum and maximum clock periods as illustrated in Figure A-3.
C
112
=10kHz:
R
=
C
2
---------------------------- -
s
p
s
can now be calculated as:
should be chosen in the range of:
C
f
=
C
should be chosen to fulfill the Gardner’s stability criteria by at least a factor of 10,
K
n
<
--------------------- -
n f
2
------------------------------------------
C
=
f
C
s
C
f
------------ -
VCO
2
f
2
20 C
ref
R
= 2* *50*10kHz/(316.7Hz/ )=9.9k =~10k
+
ref
is measured and input voltage to the VCO is adjusted
=
1
0.516
-------------- -
f
f
C
ref
p
+
2
R
2
C
;
synr
s
----- -
10
1
=
10
0.9
+
1
f
C
f
C
C
p
<
= 5.19nF =~ 4.7nF
< 25kHz
= 470pF
= 50
------------- -
4 10
f
ref
;
=
0.9
cmp
, the