SMAX-624CG-ACTEL Actel, SMAX-624CG-ACTEL Datasheet - Page 22

• Manufacturer Part Number: SMAX-624CG-ACTEL
• Description: Programming Socket Adapters & Emulators SILICON SCULPTOR ADAPTER MODULE
• Manufacturer: Actel

Specifications of SMAX-624CG-ACTEL

• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

1 -1 8
Step 1: Define Terms Used in Formula
Module
Number of logic modules switching
at f
Average logic modules switching rate
f
Module capacitance C
Input Buffer
Number of input buffers switching at f
Average input switching rate f
(Guidelines: f/5)
Input buffer capacitance C
Output Buffer
Number of output buffers switching at f
Average output buffers switching rate
f
Output buffers buffer capacitance
C
Output Load capacitance C
RCLKA
Number of Clock loads q
Capacitance of routed array clock (pF)
Average clock rate (MHz)
Fixed capacitance (pF)
RCLKB
Number of Clock loads q
Capacitance of routed array clock (pF)
Average clock rate (MHz)
Fixed capacitance (pF)
HCLK
Number of Clock loads
Variable capacitance of dedicated
array clock (pF)
Fixed capacitance of dedicated
array clock (pF)
Average clock rate (MHz)
m
p
EQO
SX Family FPGAs
(MHz) (Guidelines: f/10)
(MHz) (Guidelines: f/10)
m
(Used 50%)
(pF)
EQM
1
2
(pF)
EQI
L
(pF)
(pF)
n
(MHz)
n
p
V
m
f
C
n
f
C
p
f
C
C
q
C
f
r
q
C
f
r
s
C
C
f
m
n
p
q1
1
q2
2
1
s1
EQM
EQI
EQO
L
1
EQCR
2
EQCR
EQHV
EQHF
CCA
3.3
264
20
4.0
1
40
3.4
1
20
4.7
35
528
1.6
200
138
0
1.6
0
138
0
0.61
5
96
0
v3.2
Step 3: Calculate DC Power Dissipation
DC Power Dissipation
For a rough estimate of DC Power Dissipation, only use
P
very small number that can be considered negligible.
Step 4: Calculate Total Power Consumption
Step 5: Compare Estimated Power Consumption
against Characterized Power Consumption
The estimated total power consumption for this design is
1.46 W. The characterized power consumption for this
design at 200 MHz is 1.0164 W.
Step 2: Calculate Dynamic Power Consumption
DC
P
V
P
P
P
P
P
P
V
m × f
n × f
p × f
0.5 (q
0.5(q
0.5 (s
P
= (I
DC
DC
DC
DC
Total
Total
Total
CCI
AC
CCA
= (I
= (I
= .55 mA × 3.3 V
standby
+ X × V
= 0.001815 W
n
p
= P
= 1.461 + 0.001815
= 1.4628 W
2
m
1
= 1.461 W
× V
1
× C
× (C
× C
standby
standby
× C
× C
× C
AC
CCA
EQI
EQCR
) × V
EQO
EQHV
EQM
EQCR
+ P
OL
) × V
) × V
+C
DC
× I
CCA
× f
× f
× f
OL
L
CCA
CCA
)
q2
s1
q1
. The rest of the formula provides a
+ Y(V
) + (r
) + (C
) + (r
+ (I
2
standby
CCI
1
EQHF
× f
× f
– V
q2
q1
× f
) × V
)
OH
)
s1
) × V
)
CCR
OH
+ (I
standby
10.89
0.02112
0.000136
0.000794
0.11208
0
0
EQ 1-12
) ×