27404 Parallax Inc, 27404 Datasheet - Page 35

COMPETITION RING FOR SUMOBOT

27404

Manufacturer Part Number
27404
Description
COMPETITION RING FOR SUMOBOT
Manufacturer
Parallax Inc
Datasheet

Specifications of 27404

Accessory Type
Hobby and Education
Product
Microcontroller Accessories
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
For Use With/related Products
SumoBot®
Lead Free Status / RoHS Status
Lead free / RoHS Compliant, Contains lead / RoHS non-compliant
Problem: It took a 700 g mass (W
11 to make a 2100 g mass (W
Solution: If the system is exactly at T = f
we know that T and T
The next step is to draw separate free body diagrams for each object (see Figure 1-12).
The sum of the forces for the hanging block should add up to zero:
T =
T
T
1
1
Fy
=
T
W
W
1
=
1
1
Coefficients of friction do not have units.
coefficient of friction, multiplied by the normal force. There are no units that need to cancel
each other out. For example, if you start with a normal force that's in newtons, and multiply
by a coefficient of friction, the result will be a frictional force in newtons.
0
=
0
1
are equal and opposite:
2
) start to slide. Find the coefficient of static friction, µ
1
) hanging from this pulley system shown in Figure 1-
S,Max
, nothing is moving yet. From Figure 1-11,
Chapter 1: Mechanical Adjustments · Page 31
A friction force is always equal to the
Figure 1-11
Pulley Problem
Tension in the string
applies force equal to
weight W1 to the
block on the surface.
S
.

Related parts for 27404