IR3086AMPBF International Rectifier, IR3086AMPBF Datasheet - Page 28

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IR3086AMPBF

Manufacturer Part Number
IR3086AMPBF
Description
IC PHASE CONTROLLER OVP 20MLPQ
Manufacturer
International Rectifier
Series
XPhase™r
Datasheet

Specifications of IR3086AMPBF

Applications
Processor
Current - Supply
10mA
Voltage - Supply
8.4 V ~ 14 V
Operating Temperature
0°C ~ 125°C
Mounting Type
Surface Mount
Package / Case
20-MLPQ
Ic Function
Phase IC With Fault And OverTemp Detect
Supply Voltage Range
8.4V To 14V, 6V To 25V, 6V To 14V
Operating Temperature Range
-40°C To +150°C
Digital Ic Case Style
MLPQ
No. Of Pins
20
Rohs Compliant
Yes
Package
20-Lead MLPQ
Circuit
X-Phase Phase IC
Iout (a)
2.5A Gate Driver
Pbf
PbF Option Available
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
*IR3086AMPBF
R
Bootstrap Capacitor C
Choose C
Decoupling Capacitors for Phase IC and Power Stage
Choose C
VOLTAGE LOOP COMPENSATION
Type III compensation is used for the converter with only ceramic output capacitors. The crossover frequency and
phase margin of the voltage loop can be estimated as follows.
Choose
Choose the desired crossover frequency fc (=140kHz) around fc1 estimated above, and calculate
Choose C
CURRENT SHARE LOOP COMPENSATION
The crossover frequency of the current share loop f
loop f
Choose C
θ
C
C
C
C
R
F
f
C
PHASE41
MI
C
CP
CP
FB
DRP
SCOMP
1
1
=
=
=
=
=
=
C
90
=
10
2
4
2 (
R
. Choose the crossover frequency of current share loop f
(
π
π
(
V
PWMRMP
=
Page 28 of 33
π
=
=
R
R
I
=10k , R
FB
. 0
BST
VCC
A
CP1
SCOMP
FB
20
. 0
C
R
f
65
tan(
L
V
1
C
f
65
1
CP
6 .
+
C
E
E
PWMRMP
=
=0.1uF
=47pF to reduce high frequency noise.
=0.1uF, C
R
*
nF
)
R
*
2
R
DRP
*
. 0
R
2
3
FB
18
C
G
FB
C
=22nF
PWMRMP
R
) 5
1
E
L
PWMRMP
CS
2 .
)
1
DRP
R
E
PHASE42
=
FB
=
*
V
180
C
10
π
10
C
O
4
V
FB
R
=
π
E
DAC
3
VCCL
BST
*
FB
=
2
3
*
=
*
V
12
140
63
R
I
)
(
(
f
=768 , R
162
100
162
FB
SW
*
( *
*
=0.1uF
R
°
I
*
105
V
1
O
LE
*
10
I
*
V
V
=
+
*
10
RAMP
110
110
G
3
PWMRMP
*
=
V
V
. 1
CS
34
O
DAC
576
2
110
9
65
)
π
_
/
PHASE43
*
=
) 6
ROOM
2
0 (
5
)
π
10
=
6 .
2 (
(
. 1 (
5 .
62
=
5
(
3
*
π
*
22
33
2 .
18
f
10
*
CI
10
nF
R
140
*
2 .
=2.80k
22
*
9
10
LE
105
3
. 1
*
, choose C
=
*
10
*
(
*
05
6
12
6
10
10
2
1 [
* )
*
*
3
7 .
*
. 9
*
+
3
62
1 [
10
CI
nF
)
100
6
* 1
. 0
2
2
+
)
)
π
6
should be at least one decade lower than that of the voltage
75
10
2
=
576
*
(
*
π
100
34
10
27
f
FB
*
CI
4
. 1
3500
nF
)
*
) 3
=5.6nF
12
1
*
162
10
3 .
C
2
*
( *
CI
π
E
800
12
*
9
=3.5kHz
( *
20
22
/
0 (
3500
V
) 6
*
*
O
*
5 .
. 1
10
10
10
) 3
*
(
I
3
*
22
O
10
*
3
. 1
6
)]
,
. 0
*
*
05
and calculate C
*
10
75
3
62
F
*
/
MI
10
) 6
*
=
6
. 1 (
. 0
6
=
62
011
33
146
)
162
IR3086APbF
105
kHz
*
*
SCOMP
. 0
. 9
75
* 1
May 13, 2009
10
=
. 1
,
4
65
)
k
105
* ]
. 0
011

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