HCPL316J500E AVAGO TECH, HCPL316J500E Datasheet - Page 30

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HCPL316J500E

Manufacturer Part Number
HCPL316J500E
Description
Manufacturer
AVAGO TECH
Datasheet
As an example, the total input and output power dis-
sipation can be calculated given the following condi-
tions:
Step 1: Calculate R
To find the peak charging l
initially charged the steady-state value of V
apply the following relationship:
R
(Note from Figure 76 that the real value of I
calculated from the simple model shown.)
Step 2: Calculate total power dissipation in the HCPL-316J:
The HCPL-316J total power dissipation (P
the sum of the input-side power (P
power (P
where,
Figure 76. Typical peak I
316J output driving an IGBT rated at 600 V/100 A.
30
G
P
P
• I
• V
• V
• f
P
= ——————————
= ——————————
= 10.25 W
≈ 10.5 W (for a 1% resistor)
I
O
= —————————
T
-1
-2
-3
[V
4
3
2
1
0
18 V – 1 V – (1.5 V + (‑5 V))
= I
ON, MAX
CARRIER
[V
= P
= P
MAX. I
CC2
EE
0
OH
= I
CC2
CC1
= -5 V
20
I
O(BIAS)
@650 µA – (V
O
CC2
+ P
= 18 V
):
ON
– 1 – (V
* V
40 60 80
(V
O
= 15 kHz
* (V
, I
CC2
~ 2.0 A
CC1
HCPL-316J fig 76
OFF
+ P
I
I
2.0 A
OL,PEAK
OL,PEAK
CC2
/ V
G
I
I
ON
OFF
ON
vs. GATE RESISTANCE
minimum from I
OL
O,SWTICH
Rg (Ω)
EE2
and I
100
–V
(MAX.)
(MAX.)
+ V
= 25 V / 5 V
OFF
OL
EE
120
EE
currents vs. Rg (for HCPL-
+V
) + E
140
)]
EE
OL
160 180
SWITCH
)]
assume that the gate is
OL
peak specification:
200
* f
OL
I
) and output-side
SWITCH
may vary from the value
T
) is equal to
EE
. Therefore
Figure 77. Switching energy plot for calculating average Pswitch
(for HCPL-316J output driving an IGBT rated at 600 V/100 A).
P
PL-316J due to biasing the device.
P
PL-316J due to charging and discharging power device
gate.
E
to switching of the power device over one switching
cycle (µJ/cycle).
f
For R
= 6.05 µJ. Assume a worst-case average I
(which is given by the average of I
larly the average I
P
P
Step 3: Compare the calculated power dissipation with the abso-
lute maximum values for the HCPL-316J:
For the example,
Therefore, the power dissipation absolute maximum
rating has not been exceeded for the example.
Please refer to the following Thermal Model section for
an explanation on how to calculate the maximum junc-
tion temperature of the HCPL-316J for a given PC board
layout configuration.
SWITCH
SWITCH
I
O
O(BIAS)
O(SWITCH)
= 16.5 mA * 5.5 V = 90.8 mW
= P
= 5.5 mA * (18 V – (–5 V)) + 6.051 µJ * 15 kHz
= 126.5 mW + 90.8 mW
= 217.3 mW
P
P
I
O
G
= 90.8 mW < 150 mW (abs. max.) ) OK
= 10.5, the value read from Figure 77 is E
O(BIAS)
= 217.3 mW < 600 mW (abs. max.) ) OK
= average carrier signal frequency.
= steady-state power dissipation in the HC-
= Average Energy dissipated in HCPL-316J due
= transient power dissipation in the HC-
+ P
O,SWITCH
CC2
= 5.5 mA.
CC1H
and I
CC1
CC1L
= 16.5 mA
SWITCH
). Simi-

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