AUIRFR3806 International Rectifier, AUIRFR3806 Datasheet - Page 6

• Manufacturer Part Number: AUIRFR3806
• Description: MOSFET Power
• Manufacturer: International Rectifier

Specifications of AUIRFR3806

• Transistor Polarity: N-Channel
• Drain-source Breakdown Voltage: 60 V
• Continuous Drain Current: 43 A
• Power Dissipation: 71 W
• Mounting Style: SMD/SMT
• Package / Case: DPAK
• Gate Charge Qg: 22 nC
• Lead Free Status / Rohs Status: Details

6
Fig 15. Maximum Avalanche Energy vs. Temperature
80
60
40
20
0
25
0.001
100
0.01
0.1
Starting T J , Junction Temperature (°C)
10
0.1
1.0E-06
1
10
1E-006
1
50
Allowed avalanche Current vs avalanche
pulsewidth, tav, assuming ΔΤ j = 25°C and
Tstart = 150°C.
Fig 13. Maximum Effective Transient Thermal Impedance, Junction-to-Case
D = 0.50
TOP
BOTTOM 1.0% Duty Cycle
I D = 25A
0.10
0.05
0.01
75
0.01
0.02
0.20
0.10
0.05
100
SINGLE PULSE
( THERMAL RESPONSE )
Single Pulse
Duty Cycle = Single Pulse
1.0E-05
1E-005
125
Fig 14. Typical Avalanche Current vs.Pulsewidth
150
175
t 1 , Rectangular Pulse Duration (sec)
1.0E-04
0.0001
Notes on Repetitive Avalanche Curves , Figures 14, 15:
(For further info, see AN-1005 at www.irf.com)
1. Avalanche failures assumption:
2. Safe operation in Avalanche is allowed as long asT
3. Equation below based on circuit and waveforms shown in Figures 16a, 16b.
4. P
5. BV = Rated breakdown voltage (1.3 factor accounts for voltage increase
6. I
7. ΔT
tav (sec)
Purely a thermal phenomenon and failure occurs at a temperature far in
excess of T
during avalanche).
25°C in Figure 14, 15).
t
D = Duty cycle in avalanche = t
Z
av
av =
thJC
D (ave)
τ
J
= Allowable avalanche current.
=
τ
J
Average time in avalanche.
τ
(D, t
Allowable rise in junction temperature, not to exceed T
1
Ci= τi/Ri
Allowed avalanche Current vs avalanche
pulsewidth, tav, assuming Δ Tj = 150°C and
Tstart =25°C (Single Pulse)
τ
1
Ci
= Average power dissipation per single avalanche pulse.
av
1.0E-03
) = Transient thermal resistance, see Figures 13)
i/Ri
R
jmax
1
R
0.001
1
. This is validated for every part type.
τ
2
R
τ
P
2
2
R
D (ave)
2
R
τ
= 1/2 ( 1.3·BV·I
3
I
3
E
R
Notes:
1. Duty Factor D = t1/t2
2. Peak Tj = P dm x Zthjc + Tc
τ
av
3
3
AS (AR)
= 2DT/ [1.3·BV·Z
τ
C
av
1.0E-02
τ
Ri (°C/W)
·f
0.6086
0.9926
0.5203
= P
0.01
D (ave)
av
) = DT/ Z
·t
th
av
0.00026
0.001228
0.00812
τi (sec)
]
jmax
thJC
jmax
1.0E-01
is not exceeded.
0.1
(assumed as
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