STPS10L25G-TR STMicroelectronics, STPS10L25G-TR Datasheet - Page 2

DIODE SCHOTTKY 25V 10A D2PAK

STPS10L25G-TR

Manufacturer Part Number
STPS10L25G-TR
Description
DIODE SCHOTTKY 25V 10A D2PAK
Manufacturer
STMicroelectronics
Datasheet

Specifications of STPS10L25G-TR

Voltage - Forward (vf) (max) @ If
460mV @ 10A
Voltage - Dc Reverse (vr) (max)
25V
Current - Average Rectified (io)
10A
Current - Reverse Leakage @ Vr
800µA @ 25V
Diode Type
Schottky
Speed
Fast Recovery =< 500ns, > 200mA (Io)
Mounting Type
Surface Mount
Package / Case
D²Pak, TO-263 (2 leads + tab)
Product
Schottky Rectifiers
Peak Reverse Voltage
25 V
Forward Continuous Current
10 A
Max Surge Current
200 A
Configuration
Single
Forward Voltage Drop
0.55 V at 20 A
Maximum Reverse Leakage Current
800 uA
Operating Temperature Range
+ 150 C
Mounting Style
SMD/SMT
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Reverse Recovery Time (trr)
-
Capacitance @ Vr, F
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
497-5134-2

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Quantity
Price
Part Number:
STPS10L25G-TR
Manufacturer:
ST
0
STPS10L25D/G
STATIC ELECTRICAL CHARACTERISTICS
Pulse test:
To evaluate the maximum conduction losses use the following equation :
P = 0.22 x I
Fig. 1: Average forward power dissipation versus
average forward current.
Fig. 3: Normalized avalanche power derating
versus pulse duration.
0.001
2/5
THERMAL RESISTANCE
5.0
4.5
4.0
3.5
3.0
2.5
2.0
1.5
1.0
0.5
0.0
0.01
Symbol
Symbol
0.1
R
0.01
1
0
V
PF(av)(W)
th (j-c)
I
P
R
F
P
ARM
ARM p
*
*
1
(1µs)
(t )
2
F(AV)
0.1
Junction to case
* tp = 380 µs, < 2%
Reverse leakage current
Forward voltage drop
= 0.05
Tests Conditions
3
+ 0.013 I
4
= 0.1
1
IF(av) (A)
t (µs)
5
p
F
2
(RMS)
= 0.2
6
10
7
8
= 0.5
Parameter
100
=tp/T
9
Tj = 25 C
Tj = 125 C
Tj = 25 C
Tj = 125 C
Tj = 25 C
Tj = 125
T
10
= 1
Tests Conditions
tp
1000
11
Fig. 2: Average forward current versus ambient
temperature ( = 0.5).
Fig. 4: Normalized avalanche power derating
versus junction temperature.
1.2
0.8
0.6
0.4
0.2
12
10
8
6
4
2
0
1
0
V
I
I
I
I
0
F
F
F
F
0
P
IF(av)(A)
R
P
ARM
= 10 A
= 10 A
= 20 A
= 20 A
ARM p
= V
=tp/T
(25°C)
(t )
RRM
25
T
25
tp
50
50
Min.
Tamb(°C)
Rth(j-a)=50°C/W
Rth(j-a)=Rth(j-c)
T (°C)
j
75
75
Typ.
0.30
0.41
135
Value
1.5
100
100
Max.
0.46
0.35
0.55
0.48
800
260
125
125
Unit
Unit
C/W
mA
V
A
150
150

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