AD627ARZ Analog Devices Inc, AD627ARZ Datasheet - Page 14

IC AMP INST R-R 25MA 8SOIC

AD627ARZ

Manufacturer Part Number
AD627ARZ
Description
IC AMP INST R-R 25MA 8SOIC
Manufacturer
Analog Devices Inc
Type
Rail-to-Railr
Datasheets

Specifications of AD627ARZ

Slew Rate
0.06 V/µs
Amplifier Type
Instrumentation
Number Of Circuits
1
Output Type
Rail-to-Rail
-3db Bandwidth
80kHz
Current - Input Bias
2nA
Voltage - Input Offset
25µV
Current - Supply
60µA
Current - Output / Channel
25mA
Voltage - Supply, Single/dual (±)
2.2 V ~ 36 V, ±1.1 V ~ 18 V
Operating Temperature
-40°C ~ 85°C
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
No. Of Amplifiers
1
Input Offset Voltage
200µV
Gain Db Min
5dB
Gain Db Max
1000dB
Bandwidth
40MHz
Amplifier Output
Rail To Rail
Cmrr
77dB
Supply Voltage Range
± 1.1V To ±
Common Mode Rejection Ratio
90
Current, Input Bias
3 nA (Single), 2 nA (Dual)
Current, Input Offset
0.3 nA
Current, Supply
60 μA
Impedance, Thermal
155 °C/W
Package Type
SOIC-8
Power Dissipation
0.8 W
Resistance, Input
20 Gigaohms (Differential), 20 Gigaohms (Common-Mode)
Temperature, Operating, Range
-40 to +85 °C
Voltage, Gain
1000 V/V
Voltage, Input
-35.9 to +35 V (Single), -17.9 to +17 V (Dual)
Voltage, Input Offset
50 μV (Single), 25 μV (Dual)
Voltage, Noise
38 nV/sqrt Hz
Voltage, Supply
2.2 to ±18 V
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Gain Bandwidth Product
-
Lead Free Status / Rohs Status
RoHS Compliant part Electrostatic Device

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AD627
THEORY OF OPERATION
The AD627 is a true instrumentation amplifier, built using two
feedback loops. Its general properties are similar to those of the
classic two-op-amp instrumentation amplifier configuration but
internally the details are somewhat different. The AD627 uses a
modified current feedback scheme, which, coupled with interstage
feedforward frequency compensation, results in a much better
common-mode rejection ratio (CMRR) at frequencies above
dc (notably the line frequency of 50 Hz to 60 Hz) than might
otherwise be expected of a low power instrumentation amplifier.
In Figure 35, A1 completes a feedback loop that, in conjunction
with V1 and R5, forces a constant collector current in Q1. Assume
that the gain-setting resistor (R
and R1 complete the loop and force the output of A1 to be equal
to the voltage on the inverting terminal with a gain of nearly
1.25. A2 completes a nearly identical feedback loop that forces
a current in Q2 that is nearly identical to that in Q1; A2 also
provides the output voltage. When both loops are balanced, the
gain from the noninverting terminal to V
whereas the gain from the output of A1 to V
G
) is not present. Resistors R2
REF
–IN
2kΩ
OUT
100kΩ
R1
OUT
+V
–V
is equal to 5,
S
S
is equal to −4.
EXTERNAL GAIN RESISTOR
Figure 35. Simplified Schematic
Q1
R5
200kΩ
Rev. D | Page 14 of 24
25kΩ
R2
A1
V1
R
G
25kΩ
0.1V
R3
The inverting terminal gain of A1 (1.25) times the gain of A2
(−4) makes the gain from the inverting and noninverting
terminals equal.
The differential mode gain is equal to 1 + R4/R3, nominally 5,
and is factory trimmed to 0.01% final accuracy. Adding an
external gain setting resistor (R
amount equal to (R4 + R1)/R
AD627 is given by
Laser trims are performed on R1 through R4 to ensure that
their values are as close as possible to the absolute values in the
gain equation. This ensures low gain error and high common-
mode rejection at all practical gains.
Q2
R6
200kΩ
–V
V
+V
OUT
S
S
A2
100kΩ
2kΩ
R4
= [V
+IN
IN
(+) – V
OUTPUT
IN
(−)] × (5 + 200 kΩ/R
G
. The output voltage of the
G
) increases the gain by an
G
) + V
REF
(1)

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