SW500007 Microchip Technology, SW500007 Datasheet - Page 391

• Manufacturer Part Number: SW500007
• Description: PICC-18 PRO
• Manufacturer: Microchip Technology
• Type: Compilerr
• Series: PIC18r

Specifications of SW500007

• Supported Families: PIC18
• Core Architecture: PIC
• Software Edition: Professional
• Kit Contents: Software And Docs
• Mcu Supported Families: PIC18
• Tool Function: Compiler
• Tool Type: Compiler
• Lead Free Status / RoHS Status: Not applicable / RoHS Compliant
• For Use With/related Products: PIC18 Series
• Lead Free Status / Rohs Status: Lead free / RoHS Compliant
• Other names: 015P; 778-1002; 778-1002

Error and Warning Messages
will produce code that sets a to 5, then immediately sets b to 6. No code will be produced for the
comparison if(a == 4). If a was a global variable, it may be that other functions (particularly
interrupt functions) may modify it and so tracking the variable cannot be performed.
expression with missing or badly placed parentheses, causing the evaluation to yield a value different
to what you expected.
an infinite loop, use for(;;).
In this case the code generator can again pick up that a is assigned the value 0, then immediately
checked to see if it is equal to 10. Because a is modified during the for loop, the comparison
code cannot be removed, but the code generator will adjust the code so that the comparison is not
performed on the first pass of the loop; only on the subsequent passes. This may not reduce code
size, but it will speed program execution.
(758) constant conditional branch: possible use of = instead of ==
There is an expression inside an if or other conditional construct, where a constant is being assigned
to a variable. This may mean you have inadvertently used an assignment = instead of a compare ==,
e.g.:
will assign the value 4 to a, then , as the value of the assignment is always true, the comparison can
be omitted and the assignment to b always made. Did you mean:
This warning may indicate more than an optimization made by the compiler. It may indicate an
This warning may also be issued because you have written something like while(1). To produce
A similar situation arises with for loops, e.g.:
{
{
int a, b;
a = 5;
if(a == 4) /* this can never be false; always perform the true statement */
int a, b;
for(a=0; a!=10; a++) /* this loop must iterate at least once */
int a, b;
if(a = 4) /* this can never be false; always perform the true statement */
b = 6;
b = func(a);
b = 6;
(Code Generator)
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