IRDCIP2005C-2 International Rectifier, IRDCIP2005C-2 Datasheet - Page 8
![no-image](/images/manufacturer_photos/0/3/338/international_rectifier_sml.jpg)
IRDCIP2005C-2
Manufacturer Part Number
IRDCIP2005C-2
Description
BOARD DEMO SYNC BUCK CONVETER
Manufacturer
International Rectifier
Specifications of IRDCIP2005C-2
Package
Design Kit
Featured Part
iP2005C
Input Voltage (v)
8.5V - 14.5V
Output Voltage (v)
0.8V - 5.0V
Total Current
30A
Phases
1
Switching Frequency (khz)
500kHz
Calculating Power Loss and SOA for Different Operating Conditions
To calculate Power Loss for a given set of operation conditions, the following procedure should be
followed:
Power Loss Procedure
To calculate the Safe Operating Area (SOA) for a given set of operating conditions, the following
procedure should be followed:
SOA Procedure
Design Example
Operating Conditions
Output Current = 30A
Switching Freq = 750 kHz
Calculating Maximum Power Loss:
(Figure 1) Maximum power loss = 7.0W
(Figure 3) Normalized power loss for input voltage ≈ 0.975
(Figure 5) Normalized power loss for output inductor ≈ 1.012
(Figure 6) Normalized power loss for switch frequency ≈ 0.88
Calculated Maximum Power Loss ≈ 7.0W x 0.975 x 1.0 x 1.012 x 0.88 ≈ 6.09W
www.irf.com
1. Determine the maximum current and obtain the maximum power loss from figure 1
2. Use the normalized curves to obtain power loss values that match the operating conditions in
3. The maximum power loss under the application conditions is then the product of the power
1. Determine the maximum PCB and CASE temperature at the maximum operating current for
2. Use the normalized curves to obtain SOA temperature adjustments that match the operating
3. Then, add the sum of the SOA temperature adjustments to the T
the application
loss from figure 1and the normalized values.
each iP2005C
conditions in the application
:
Inductor = 0.2µH
Input Voltage = 10V
04/09/2009
Output Voltage = 1.3V
Drive Voltage (VDD) = 5V
X
axis intercept in figure 2
iP2005CPbF
PD-60360
8