IRPLHALO1E International Rectifier, IRPLHALO1E Datasheet - Page 12

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IRPLHALO1E

Manufacturer Part Number
IRPLHALO1E
Description
KIT HALOGIN CONVERTER 100VA
Manufacturer
International Rectifier
Datasheet

Specifications of IRPLHALO1E

Main Purpose
Lighting, Ballast Control
Utilized Ic / Part
IR2161
Lead Free Status / RoHS Status
Lead free / RoHS non-compliant
Secondary Attributes
-
Embedded
-
Primary Attributes
-
Other names
*IRPLHALO1E
IRPLHALO1E
The transformer selection procedure is as follows:
1.
2.
3.
4.
12
Select the correct core size for the maximum load at 30kHz. Use the manufacturer’s core
data to determine the maximum throughput power at this frequency.
Calculate the number of turns required at the primary
Where Bmax (maximum flux density in Teslas) can be obtained from the core manufactur-
ers data for the Ferrite material operating at a temperature of 100 degrees C and Ae is the
cross sectional area of the magnetic path in mm
Vpk may be considered to be 400V and Ton(max) may be considered to be 18uS.
Calculate the number of turns required at the secondary.
Determine the leakage inductance.
This can only be done by measurement. Simply short out the secondary and measure the
primary inductance with an LCR bridge. The amount of leakage inductance depends on the
physical construction of the transformer, the better the primary and secondary windings are
coupled, the lower the leakage inductance will be. However, in this application some leak-
age inductance is desirable to limit the primary current if the secondary is short circuited. It
is also important to consider that a high isolation breakdown voltage (4kV) is required in this
application between the primary and secondary windings, for safety certification of the con-
vertor. This means that winding the primary and secondary close together is not possible
and therefore, some leakage inductance will result.
In some designs the output transformer is purposely designed to have a high leakage
inductance in order to limit the primary current under short circuit conditions and therefore
allow smaller half bridge MOSFETs to be used. In this case the short circuit primary current
may be too small to trigger the short circuit protection, the result being that the system will
take longer to shut down because only the overload threshold is exceeded at the CS pin.
This is unlikely to cause any problems but should be considered.
Np
Ns
(min)
. 2
Np
Vac
Vpk
.
Vout
2
(
rms
B
(max)
Ton
(
rms
)
(max)
)
Ae
2
.
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