ICL7106CPLZ Intersil, ICL7106CPLZ Datasheet - Page 4
ICL7106CPLZ
Manufacturer Part Number
ICL7106CPLZ
Description
IC ADC 3.5DIGIT LCD/LED LP 40DIP
Manufacturer
Intersil
Specifications of ICL7106CPLZ
Display Type
LCD
Configuration
7 Segment
Digits Or Characters
A/D 3.5 Digits
Voltage - Supply
4.75 V ~ 5.25 V
Operating Temperature
0°C ~ 70°C
Mounting Type
Through Hole
Package / Case
40-DIP (0.600", 15.24mm)
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Current - Supply
-
Interface
-
Lead Free Status / Rohs Status
RoHS Compliant part
Electrostatic Device
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
ICL7106CPLZ
Manufacturer:
INTERSIL
Quantity:
30 000
Company:
Part Number:
ICL7106CPLZ
Manufacturer:
INTERSIL
Quantity:
13 343
Part Number:
ICL7106CPLZ
Manufacturer:
INTERSIL
Quantity:
20 000
Electrical Specifications
NOTES:
Typical Applications and Test Circuits
DISPLAY DRIVER ICL7107 ONLY
Segment Sinking Current
3. Unless otherwise noted, specifications apply to both the ICL7106 and ICL7107 at T
4. Back plane drive is in phase with segment drive for “off” segment, 180 degrees out of phase for “on” segment. Frequency is 20 times conversion
5. Not tested, guaranteed by design.
6. Sample Tested.
FIGURE 1. ICL7106 TEST CIRCUIT AND TYPICAL APPLICATION WITH LCD DISPLAY COMPONENTS SELECTED FOR 200mV FULL
FIGURE 2. ICL7107 TEST CIRCUIT AND TYPICAL APPLICATION WITH LED DISPLAY COMPONENTS SELECTED FOR 200mV FULL
of Figure 1. ICL7107 is tested in the circuit of Figure 2.
rate. Average DC component is less than 50mV.
SCALE
SCALE
PARAMETER
Except Pins AB4 and POL
Pin AB4 Only
Pin POL Only
R
R
3
3
4
(Note 3) (Continued)
C
C
4
4
R
R
R
R
1
4
1
4
+5V
C
C
V+ = 5V, Segment Voltage = 3V
ICL7106, ICL7107, ICL7107S
1
1
R
R
5
ICL7107
5
ICL7106
+
DISPLAY
+
DISPLAY
IN
C
IN
C
5
5
-
-
C
C
2
2
+
R
R
TEST CONDITIONS
2
2
9V
-
C
C
3
-5V
3
DISPLAY
DISPLAY
A
= 25
o
C, f CLOCK = 48kHz. ICL7106 is tested in the circuit
MIN
10
5
4
TYP
16
8
7
C
C
C
C
C
R
R
R
R
R
C
C
C
C
C
R
R
R
R
R
1
2
3
4
5
1
2
3
4
5
1
2
3
4
5
1
2
3
4
5
= 0.1µF
= 0.47µF
= 0.22µF
= 100pF
= 0.02µF
= 24kΩ
= 47kΩ
= 100kΩ
= 1kΩ
= 1MΩ
= 0.1µF
= 0.47µF
= 0.22µF
= 100pF
= 0.02µF
= 24kΩ
= 47kΩ
= 100kΩ
= 1kΩ
= 1MΩ
MAX
-
-
-
UNIT
mA
mA
mA
FN3082.8