2SA1515S_10 ROHM [Rohm], 2SA1515S_10 Datasheet - Page 2

• Manufacturer Part Number: 2SA1515S_10
• Description: Medium Power Transistor (-32V,-1A)
• Manufacturer: ROHM [Rohm]

Packaging specifications and h
h
Electrical characteristics curves
○
2SA1515S / 2SB1237
c
www.rohm.com
Type
2SA1515S
2SB1237
FE
1000
-500
-200
-100
500
200
100
200
100
-50
-20
-10
50
50
20
2010 ROHM Co., Ltd. All rights reserved.
values are classified as follows :
Item
-5
-2
-1
−1
h
Fig.1 Grounded emitter
−1
Fig.7 Gain bandwidth product
0
FE
BASE TO EMITTER VOLTAGE : V
Ta
−2
-0.2 -0.4 -0.6 -0.8 -1.0 -1.2 -1.4 -1.6
COLLECTOR CURRENT : I
Fig.4 DC current gain vs.
−2
=
−
100 C
EMITTER CURRENT : I
25 C
55 C
propagation characteristics
−5 −10 −20
vs. emitter current
120 to 270
h
QR
QR
Ta=100 C
FE
−5
collector current
−55 C
Q
25 C
−10
Package
Code
Basic ordering unit (pieces)
−50 −100 −200 −500−1000
−20
180 to 390
E
(mA)
C
V
V
Ta=25 C
V
(mA)
R
CE
CE
CE
−50 −100
(ΙΙ)
= −
= − 3V
BE
= − 5V
(V)
6V
FE
COLLECTOR TO EMITTER VOLTAGE : V
−500
−400
−300
−200
−100
100
−0.02
−0.01
−0.05
Fig.8 Collector output capacitance
5000
50
20
10
−0.5
−0.2
−0.1
−1
TP
Fig.2 Grounded emitter output
0
−
−1 −2
0
−
COLLECTOR TO BASE VOLTAGE : V
Fig.5 Collector-emitter saturation
0.5
−3.0
−3.5
−4.0
−4.5
−5.0
Ta=25 C
I
C
Taping
/I
B
COLLECTOR CURRENT : I
=10
vs.collector-base voltage
−0.4
−5 −10 −20
characteristics
−
voltage vs. collector current
1
2500
TU2
−
−0.8
−
2
2/3
−50 −100 −200 −500 −1000 −2000
−2.5
−1.2
−
5
C
−
−1.6
Ta=25 C
(mA)
f=1MHz
I
I
Ta=25 C
E
10
B
=0A
=0mA
−2.0
−1.5
−1.0
−0.5
CE
CB
(V)
−
−2.0
(V)
20
1000
−0.05
−0.02
−0.01
500
200
100
−1.0
−0.8
−0.6
−0.4
−0.2
−0.5
−0.2
−0.1
50
−5
−2
−1
COLLECTOR TO EMITTER VOLTAGE : V
−0.1
0
−1
−1
Fig.6 Collector-emitter saturation
l
−0.2
Fig.9 Safe operation area
C
−2
Fig.3 DC current gain vs.
= −300mA
COLLECTOR CURRENT : I
−2
P
P
W
W
BASE CURRENT : I
−5 −10 −20
I
−0.5 −1
=10ms
=100ms
C Max
voltage vs. base current
(2SB1237)
collector current
.
DC
−5
∗
2010.04 - Rev.D
∗
l
∗
C
= −500mA
−10
−2
Data Sheet
−50 −100 −200 −500
V
CE
−5 −10 −20
−20
= −3V
Ta=25 C
∗
B
Single pulse
−1V
(mA)
C
(mA)
Ta=25 C
Ta=25 C
(Ι)
−50 −100
CE
−1000
−50
(V)