MAX8520 MAXIM [Maxim Integrated Products], MAX8520 Datasheet - Page 5

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MAX8520

Manufacturer Part Number
MAX8520
Description
Smallest TEC Power Drivers for Optical Modules
Manufacturer
MAXIM [Maxim Integrated Products]
Datasheet

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ELECTRICAL CHARACTERISTICS (continued)
(V
-40°C to +85°C, unless otherwise noted.) (Note 7)
Note 3: Enter 1MHz mode by tying a 60kΩ resistor from FREQ to ground for the MAX8520, and tying FREQ to V
Note 4: Includes PFET leakage.
Note 5: Duty-cycle specification is guaranteed by design and not production tested.
Note 6: CTLI Gain is defined as:
Note 7: Specifications to -40°C are guaranteed by design and not production tested.
(V
MAXV Threshold Accuracy
MAXV, MAXI_ Input Bias Current
CTLI Gain
CTLI Input Resistance
Error-Amp Transconductance
V
DD
DD
ITEC
90
80
70
60
50
40
30
20
10
0
= PV
= 5V, circuit of Figure 1, T
0
Accuracy
DD
0.2
EFFICIENCY vs. TEC CURRENT
PARAMETER
FREQ = 500kHz
1 = PV
A
(V
0.4
CTLI
DD
TEC CURENT (A)
= 5V, R
0.6
DD
_______________________________________________________________________________________
=
2 = SHDN = 5V, 1MHz mode (Note 2). PGND1 = PGND2 = GND, CTLI = MAXV = MAXIP = MAXIN = REF, T
0.8
TEC
(
FREQ = 1MHz
V
1.0
OS
= 2Ω)
V
1
CTLI
1.2
A
= +25°C, unless otherwise noted)
V
1.4
CS
I
MAXI_-BIAS
SYMBOL
)
1.6
I
A
R
MAXV-
BIAS
g
CTLI
CTLI
m
,
Smallest TEC Power Drivers for
90
80
70
60
50
40
30
20
10
V
V
V
V
V
V
1MΩ terminated at REF
V
0
MAXV
DD
MAXV
DD
MAXV
CTLI
OS1
0
= 5V
= 3V
0.2
to V
= 0.5V to 2.5V (Note 6)
EFFICIENCY vs. TEC CURRENT
FREQ = 500kHz
= V
= V
= V
(V
DD
CS
0.4
REF
REF
MAXI_
= 3.3V, R
= ±100mV, V
TEC CURRENT (A)
0.6
x 0.67, V
x 0.33, V
CONDITIONS
= 0.1V or 1.5V
0.8
TEC
FREQ = 1MHz
Typical Operating Characteristics
1.0
= 1.3Ω)
OS1
OS1
OS1
1.2
to V
to V
= V
1.4
OS2
OS2
DD
1.6
= ±4V,
= ±2V,
/2
Optical Modules
OUTPUT VOLTAGE RIPPLE
MIN
-0.1
9.5
0.5
-10
50
-2
-3
COMMON-MODE
400ns/div
DD
for the MAX8521.
MAX8520/21 toc03
MAX
+0.1
10.5
+10
160
2.0
+2
+3
C
V
20mV/div
AC-COUPLED
V
20mV/div
AC-COUPLED
I
TEC
UNITS
OS2
OS1
2
MΩ
= C
V/V
µA
µS
%
%
%
= 1A
7
A
= 1µF
5
=

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