LT1801 LINER [Linear Technology], LT1801 Datasheet - Page 9
![no-image](/images/no-image-200.jpg)
LT1801
Manufacturer Part Number
LT1801
Description
Dual/Quad 80MHz, 25V/?s Low Power Rail-to-Rail Input and Output Precision Op Amps
Manufacturer
LINER [Linear Technology]
Datasheet
1.LT1801.pdf
(20 pages)
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
LT1801CDD
Manufacturer:
LT
Quantity:
10 000
Part Number:
LT1801CDD
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Part Number:
LT1801CDD#PBF
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Company:
Part Number:
LT1801CDD#PBF/I
Manufacturer:
LT
Quantity:
87
Company:
Part Number:
LT1801CMS8
Manufacturer:
LT
Quantity:
10 000
Part Number:
LT1801CMS8
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Company:
Part Number:
LT1801CMS8#PBF
Manufacturer:
LT
Quantity:
1 418
Part Number:
LT1801CMS8#PBF
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Company:
Part Number:
LT1801CMS8#TRPBF
Manufacturer:
LINEAR
Quantity:
6 015
Part Number:
LT1801CMS8#TRPBF
Manufacturer:
LINEAR/凌特
Quantity:
20 000
TYPICAL PERFOR A CE CHARACTERISTICS
–200
–300
–400
–500
–100
500
400
300
200
100
35
30
25
20
15
10
5
0
–250
0
0
V
(PNP Stage)
Offset Voltage
vs Input Common Mode Voltage
V
V
OS
S
CM
= 5V, 0V
INPUT COMMON MODE VOLTAGE (V)
Distribution, V
= 0V
–150
INPUT OFFSET VOLTAGE (µV)
1
T
T
T
A
A
A
= –55°C
= 125°C
= 25°C
–50
0.001
2
0.01
0.1
10
1
0.01
Output Saturation Voltage
vs Load Current (Output Low)
V
T
CM
A
S
T
50
3
A
= –55°C
= 5V, 0V
= 125°C
= 0V
V
TYPICAL PART
S
= 5V, 0V
0.1
W
150
LOAD CURRENT (mA)
4
18012 G01
T
18012 G04
A
= 25°C
U
250
5
1
10
–0.6
–0.8
–0.2
–0.4
–1.0
45
40
35
30
25
20
15
10
1.0
0.8
0.6
0.4
0.2
5
0
–2000
0
–1
V
(NPN Stage)
Input Bias Current
vs Common Mode Voltage
18012 G07
V
V
V
OS
S
CM
S
= 5V, 0V
= 5V, 0V
INPUT COMMON MODE VOLTAGE (V)
100
Distribution, V
= 5V
–1200
0
T
T
T
INPUT OFFSET VOLTAGE (µV)
A
A
A
= 25°C
= 125°C
= –55°C
1
–400
2
CM
3
400
= 5V
0.001
4
0.01
1200
0.1
10
1
0.01
Output Saturation Voltage
vs Load Current (Output High)
18012 G02
5
V
T
18012 G05
T
S
A
A
= 5V, 0V
= –55°C
= 125°C
2000
6
0.1
LOAD CURRENT (mA)
T
A
–0.1
= 25°C
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
3
2
1
0
4
–60
1
0
Supply Current vs Supply Voltage
Input Bias Current
vs Temperature
PER AMPLIFIER
1
–40 –20
NPN ACTIVE
PNP ACTIVE
V
V
V
V
S
S
LT1801/LT1802
2
CM
CM
= 5V, 0V
= 5V, 0V
TOTAL SUPPLY VOLTAGE (V)
10
= 5V
= 1V
3
TEMPERATURE (°C)
4
18012 G08
0
5
100
6
20
T
T
A
A
T
7
A
= –55°C
= 125°C
= 25°C
40
8
9 10
60
18012 G06
18012 G03
18012fb
11
9
80
12