2sa2096 ROHM Co. Ltd., 2sa2096 Datasheet - Page 2

• Manufacturer Part Number: 2sa2096
• Description: Power Transistor -60v, -5a
• Manufacturer: ROHM Co. Ltd.

Transistors
∗1 Non repetitive pulse
∗2 See Switching charactaristics measurement circuits
Collector-emitter breakdown voltage
Collector-base breakdown voltage
Emitter-base breakdown voltage
Collector cut-off current
Emitter cut-off current
Collector-emitter saturation voltage
DC current gain
Transition frequency
Corrector output capacitance
Turn-on time
Storage time
Fall time
−0.001
1000
Electrical characteristics (Ta=25GC)
h
Electrical characteristic curves
−0.01
−100
100
−0.1
−10
FE
10
−0.001
−1
1
−0.1
120−270
COLLECTOR TO EMITTER VOLTAGE : V
RANK
Single
non repetitive
Pulsed
Fig.4 DC Current Gain vs.
Fig.1 Safe Operating Area
Q
COLLECTOR CURRENT : I
Parameter
−0.01
−0.1
Collector Current
−0.1
−1
DC
100ms
V
V
V
CE
CE
CE
= −5V
= −3V
= −2V
−10
−1
Ta=25°C
C
(A)
(ΙΙ)
10ms
1ms
100µ
CE
(V)
−10
−100
Symbol
V
BV
BV
BV
Tstg
CE (sat)
Cob
Ton
I
I
h
CBO
EBO
Tf
f
FE
CEO
CBO
EBO
T
−0.001
1000
−0.01
100
−0.1
−10
Fig.5 Collector-Emitter Saturation
10
−1
−60
−60
120
Min.
−0.01
−0.001
−6
−
−
−
−
−
−
−
−
Voltage vs. Collector Current
COLLECTOR CURRENT : I
COLLECTOR CURRENT : I
Ta=125°C
Ta=25°C
Ta= −40°C
Fig.2 Switching Time
−0.01
Tstg
−200
Ton
Typ.
170
130
Tf
75
25
25
−0.1
−
−
−
−
−
−
−0.1
−500
−1.0
−1.0
Max.
270
−
−
−
−
−
−
−
−
−1
I
Ta=25°C
V
I
C
C
−1
CC
/ I
/ I
B
= −25V
B
C
C
=10 / 1
=10 / 1
(A)
(A)
MHz
Unit
mV
µA
µA
pF
ns
ns
ns
V
V
V
−
(Ι)
−10
−10
I
I
I
V
V
I
I
V
I
V
I
f=10MHz
V
I
f=1MHz
I
I
I
V
C
C
E
C
B
C
E
E
C
B1
B2
= −100µA
CB
EB
= −0.3mA
CE
CE
=100mA
CB
=0mA
CC
= −1mA
= −100µA
= −3mA
= −100mA
= −5.0A
= −500mA
=500mA
= −40V
= −4V
= −2V
= −10V
= −10V
−25V
Condition
−0.001
1000
−0.01
100
−0.1
−10
Fig.6 Collector-Emitter Saturation
10
−1
−0.001
−0.001
1
Ta=125°C
Ta=25°C
Ta= −40°C
Fig.3 DC Current Gain vs.
Voltage vs. Collector Current
COLLECTOR CURRENT : I
COLLECTOR CURRENT : I
I
I
I
C
C
C
/ I
/ I
/ I
−0.01
−0.01
B
B
B
=100/1
=20/1
=10/1
Collector Current
Rev.A
∗1
∗1
∗2
−0.1
−0.1
2SA2096
−1
−1
V
Ta=25°C
CE
C
C
= −2V
(A)
(Ι)
(A)
2/3
(ΙΙ)
−10
−10