clc450 National Semiconductor Corporation, clc450 Datasheet - Page 4

• Manufacturer Part Number: clc450
• Description: Single Supply, Low-power, High Output, Current Feedback Amplifier
• Manufacturer: National Semiconductor Corporation

http://www.national.com
+5V Typical Performance
-30
-40
-50
-60
-70
-80
-30
-40
-50
-60
-70
1M
1M
Non-Inverting Frequency Response
Frequency Response vs. V
Gain Flatness
2nd Harmonic Distortion, R
3rd Harmonic Distortion, R
0
0
Phase
V
Gain
o
= 1V
0.5
0.5
10
pp
Output Amplitude (V
Output Amplitude (V
10MHz
5MHz
2MHz
1MHz
Frequency (MHz)
R
Frequency (Hz)
Frequency (Hz)
f
A
= 845
v
1
1
= 2
10M
10M
V
R
V
o
o
V
f
= 2.5V
A
= 845
o
= 2V
v
R
= 0.1V
10MHz
= 5
5MHz
2MHz
A
f
1MHz
= 845
v
20
1.5
1.5
pp
= 10
pp
pp
o
L
L
pp
pp
= 100
= 25
)
)
2
2
R
V
100M
100M
f
o
A
= 1.1k
= 1V
v
= 1
pp
2.5
2.5
30
(A
0
-90
-180
-270
-360
-450
v
= +2, R
-20
-30
-40
-50
-60
-70
3.5
2.5
-55
-60
-65
-70
-75
-80
-85
-90
4
3
f
0.1k
= 1k , R
1M
1M
3rd Harmonic Distortion, R
Frequency Response vs. C
Equivalent Input Noise
2nd Harmonic Distortion, R
Inverting Frequency Response
0
0
1k
Phase
V
V
Gain
+
-
o
o
= 1V
= 1V
C
0.5
0.5
1k
1k
R
L
s
= 100pF
Output Amplitude (V
Output Amplitude (V
pp
pp
= 20
L
R
C
= 100 , V
R
R
s
Frequency (Hz)
Frequency (Hz)
Frequency (Hz)
L
C
s
= 46.4
C
A
f
= 10pF
= 866
L
R
L
v
10k
Non-Inverting Current 6.9pA/ Hz
= -2
= 1000pF
s
1
1
10M
10M
= 6.7
10MHz
5MHz
2MHz
1MHz
R
Inverting Current 8.5pA/ Hz
4
A
f
1k
= 825
v
R
= -5
A
f
100k
Voltage 3.0nV/ Hz
1.5
v
= 787
1.5
s
= -10
= +5V
L
L
L
pp
pp
= 25
= 1k
)
1M
)
2
2
R
1
100M
f
100M
10MHz
, V
A
5MHz
1MHz
= 1.1k
2MHz
v
= -1
cm
10M
2.55
2.5
= V
12
11
10
9
8
7
6
-180
-270
-360
-450
-540
-630
EE
+ (V
s
140
120
100
-40
-50
-60
-70
-80
-90
-50
-55
-60
-65
-70
-75
-80
-85
-40
-50
-60
-70
-80
-90
80
60
40
/2), R
1M
1M
1k
2nd & 3rd Harmonic Distortion
3rd Harmonic Distortion, R
Frequency Response vs. R
Open Loop Transimpedance Gain, Z(s)
2nd Harmonic Distortion, R
0
0
Phase
V
Gain
Phase
L
V
o
R
Gain
o
= 2V
L
tied to V
= 1V
2nd
= 1k
10k
0.5
0.5
10MHz
R
5MHz
2MHz
pp
1MHz
Output Amplitude (V
pp
L
Output Amplitude (V
= 25
Frequency (Hz)
Frequency (Hz)
Frequency (Hz)
100k
cm
1
1
10M
, unless specified)
R
L
R
= 1k
L
= 100
2nd
1M
1.5
1.5
L
L
L
R
pp
pp
R
= 1k
L
= 100
L
10M
)
)
= 100
3rd
3rd
= 1k
2
2
R
L
100M
10MHz
5MHz
2MHz
= 100
1MHz
100M
10M
2.5
2.5
0
-90
-180
-270
-360
-450
225
180
135
90
45
0