clc453 National Semiconductor Corporation, clc453 Datasheet - Page 4

• Manufacturer Part Number: clc453
• Description: Single Supply, Low-power, High Output, Programmable Buffer
• Manufacturer: National Semiconductor Corporation

http://www.national.com
+5V Typical Performance
-44
-46
-48
-50
-52
-54
-56
-58
-60
-45
-50
-55
-60
-65
-70
-75
-80
1M
1M
Frequency Response
Frequency Response vs. V
Gain Flatness
2nd Harmonic Distortion, R
3rd Harmonic Distortion, R
0
0
0
V
V
o
Phase
Gain
o
= 0.5V
= 0.5V
0.5
0.5
Output Amplitude (V
Output Amplitude (V
pp
pp
Frequency (MHz)
Frequency (Hz)
Frequency (Hz)
10
1
1
10M
10M
V
V
o
o
V
V
= 2.5V
= 0.1V
o
o
= 1V
= 2V
A
1.5
1.5
pp
v
pp
pp
pp
A
= 1
v
10MHz
10MHz
2MHz
5MHz
1MHz
5MHz
2MHz
1MHz
20
= 1
A
o
L
A
L
v
v
pp
pp
A
(A
= 100
= -1
= -1
= 25
v
)
)
= 2
2
2
v
100M
= +1)
100M
A
v
= 2
2.5
2.5
30
(A
0
-90
-180
-270
-360
-450
v
= +2, R
3.2
3.1
2.9
2.8
-35
-40
-45
-50
-55
-60
-65
-70
-75
-60
-65
-70
-75
-80
-85
3
L
1M
1M
Frequency Response vs. V
Equivalent Input Noise
1k
Frequency Response vs. R
3rd Harmonic Distortion, R
2nd Harmonic Distortion, R
0
0
= 100 , V
V
o
Phase
Gain
= 0.5V
10MHz
5MHz
1MHz
0.5
0.5
pp
Output Amplitude (V
Output Amplitude (V
100k
s
Frequency (Hz)
Frequency (Hz)
Frequency (Hz)
= +5V
2MHz
10M
Non-Inverting Current 7.5pA/ Hz
1
1
10M
Inverting Current 10.5pA/ Hz
V
4
V
o
1
o
= 1V
, V
Voltage 2.85nV/ Hz
R
= 2.5V
R
1.5
1.5
L
R
L
= 1k
L
R
pp
cm
= 100
V
10MHz
1M
2MHz
= 1k
5MHz
1MHz
L
o
= 25
pp
= 0.1V
o
L
L
L
= V
pp
pp
R
(A
= 25
= 1k
L
100M
)
)
= 100
v
2
2
V
pp
EE
R
100M
= -1)
o
L
= 2V
= 25
+ (V
pp
10M
2.5
2.5
s
/2), R
0
-90
-180
-270
-360
-450
12.5
10
7.5
5
2.5
L
tied to V
-40
-50
-60
-70
-80
-90
-60
-65
-70
-75
-80
-60
-65
-70
-75
-80
-85
-90
-95
1M
1M
1M
Frequency Response vs. V
Frequency Response vs. C
2nd & 3rd Harmonic Distortion
2nd Harmonic Distortion, R
3rd Harmonic Distortion, R
0
0
R
V
V
1k
L
o
o
2nd
+
= 1k
-
= 0.5V
= 2V
cm
C
1k
0.5
0.5
R
, unless specified)
L
pp
R
s
= 100pF
Output Amplitude (V
Output Amplitude (V
pp
L
= 21
= 100
2nd
R
C
R
Frequency (Hz)
s
C
Frequency (Hz)
L
Frequency (Hz)
s
= 49.9
R
C
L
= 10pF
L
= 1000pF
s
= 7.0
1
1
10M
10M
10MHz
2MHz
5MHz
1MHz
1k
V
V
o
V
o
= 0.1V
1.5
1.5
o
= 2V
= 2.5V
pp
R
o
pp
L
L
R
L
L
pp
pp
L
(A
pp
= 1k
10MHz
= 100
= 100
5MHz
2MHz
1MHz
3rd
3rd
= 1k
)
)
v
2
2
V
= 2)
100M
100M
o
= 1V
pp
10M
2.5
2.5