LM323 ON Semiconductor, LM323 Datasheet - Page 5

• Manufacturer Part Number: LM323
• Description: 3-AMPERE/ 5 VOLT POSITIVE VOLTAGE REGULATORS
• Manufacturer: ON Semiconductor

Design Considerations
designed with Thermal Overload Protection that shuts down
the circuit when subjected to an excessive power overload
condition, Internal Short Circuit Protection that limits the
maximum current the circuit will pass, and Output Transistor
Safe–Area Compensation that reduces the output short
circuit current as the voltage across the pass transistor is
increased.
capacitors are not required. However, it is recommended that
the regulator input be bypassed with a capacitor if the
MOTOROLA ANALOG IC DEVICE DATA
The LM323,A series of fixed voltage regulators are
In many low current applications, compensation
2.5
2.0
1.5
1.0
0.5
–0.2
–0.4
–0.6
0.8
0.6
0.4
0.2
1.0
0.5
–90
0
0
–50
0
Figure 11. Line Transient Response
V out = 50 mV
Figure 9. Dropout Voltage
T J , JUNCTION TEMPERATURE ( C)
–10
10
30
t, TIME ( s)
20
I out = 3.0 A
I out = 0.5 A
70
I out = 150 mA
C O = 0
T J = 25 C
I out = 1.0 A
110
30
APPLICATIONS INFORMATION
150
40
LM323, A
190
regulator is connected to the power supply filter with long wire
lengths, or if the output load capacitance is large. An input
bypass capacitor should be selected to provide good
high–frequency characteristics to insure stable operation
under all load conditions. A 0.33 F or larger tantalum, mylar,
or other capacitor having low internal impedance at high
frequencies should be chosen. The bypass capacitor should
be mounted with the shortest possible leads directly across
the regulator’s input terminals. Normally good construction
techniques should be used to minimize ground loops and
lead resistance drops since the regulator has no external
sense lead.
8.0
6.0
4.0
2.0
–0.1
–0.2
–0.3
0.3
0.2
0.1
1.5
1.0
0.5
0
5.0
0
0
0
Figure 12. Load Transient Response
Figure 10. Short Circuit Current
10
V in , INPUT VOLTAGE (Vdc)
10
V in = 10 V
C O = 0
T J = 25 C
t, TIME ( s)
15
20
30
20
T J = 0 C
T J = 25 C
T J = 125 C
40
5
25