LM4819MX National Semiconductor, LM4819MX Datasheet - Page 12

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LM4819MX

Manufacturer Part Number
LM4819MX
Description
IC AMP AUDIO PWR .35W MONO 8SOIC
Manufacturer
National Semiconductor
Series
Boomer®r
Type
Class ABr
Datasheets

Specifications of LM4819MX

Output Type
1-Channel (Mono)
Max Output Power X Channels @ Load
350mW x 1 @ 16 Ohm
Voltage - Supply
2 V ~ 5.5 V
Features
Depop, Differential Inputs, Shutdown
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Other names
LM4819MXTR

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Application Information
In order to eliminate "clicks and pops", all capacitors must be
discharged before turn-on. Rapidly switching V
allow the capacitors to fully discharge, which may cause
"clicks and pops".
AUDIO POWER AMPLIFIER DESIGN EXAMPLE
parameters:
The design begins by specifying the minimum supply voltage
necessary to obtain the specified output power. To find this
minimum supply voltage, use the Output Power vs. Supply
Voltage graph in the Typical Performance Characteristics
section. From the graph for a 16Ω load, (graphs are for 8Ω,
16Ω, and 32Ω loads) the supply voltage for 100mW of output
power with 1% THD+N is approximately 3.15 volts.
Additional supply voltage creates the benefit of increased
headroom that allows the LM4819 to reproduce peaks in
excess of 100mW without output signal clipping or audible
distortion. The choice of supply voltage must also not create
a situation that violates maximum dissipation as explained
above in the Power Dissipation section. For example, if a
3.3V supply is chosen for extra headroom then according to
Equation (3) the maximum power dissipation point with a
16Ω load is 138mW. Using Equation (4) the maximum am-
bient temperature is 121˚C for the MUA08A package and
126˚C for the M08A package.
After satisfying the LM4819’s power dissipation require-
ments, the minimum differential gain is found using Equation
(6).
Given:
The following are the desired operational
Power Output
Load Impedance
Input Level
Input Impedance
Bandwidth
100Hz–20kHz
(Continued)
1Vrms (max)
DD
±
100mW
0.25dB
may not
20kΩ
16Ω
11
Thus a minimum gain of 1.27 V/V allows the LM4819 to
reach full output swing and maintain low noise and THD+N
performance. For this example, let A
er’s overall gain is set using the input (R
resistors. With the desired input impedance set to 20kΩ, the
feedback resistor is found using Equation (7).
The value of R
The last step in this design example is setting the amplifier’s
-3dB frequency bandwidth. To achieve the desired
pass band magnitude variation limit, the low frequency re-
sponse must extend to at least one-fifth the lower bandwidth
limit and the high frequency response must extend to at least
five times the upper bandwidth limit. The gain variation for
both response limits is 0.17dB, well with in the
desired limit.
The results are:
As mentioned in the External Components section, R
C
band pass frequency limit. Find the coupling capacitor’s
value using Equation (8).
C
product of the desired high frequency cutoff (100kHz in this
example) and the differential gain, A
per pass band response limit. With A
100kHz, the closed-loop gain bandwidth product (GBWP) is
127kHz. This is less than the LM4819’s 900kHz GBWP. With
this margin the amplifier can be used in designs that require
more differential gain while avoiding performance restricting
bandwidth limitations.
i
i
≥ 0.398µF, a standard value of 0.39µF will be used. The
create a high pass filter that sets the amplifier’s lower
f
f
L
H
= 100Hz/5 = 20Hz
= 20 kHz*5 = 100kHz
F
is 13kΩ.
R
F
/R
C
i
i
= A
≥ 1/(2πR
VD
/2 (V/V)
i
f
c
) (F)
VD
VD
, determines the up-
VD
i
= 1.27. The amplifi-
) and feedback (R
= 1.27 and f
www.national.com
±
±
0.25dB
0.25dB
i
and
H
(6)
(7)
(8)
F
=
)

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