HCPL-2611-020 Avago Technologies US Inc., HCPL-2611-020 Datasheet - Page 12

• Manufacturer Part Number: HCPL-2611-020
• Manufacturer: Avago Technologies US Inc.

Specifications of HCPL-2611-020

• Number Of Elements: 1
• Input Type: DC
• Output Type: Open Collector
• Forward Voltage: 1.75V
• Forward Current: 20mA
• Output Current: 50mA
• Isolation Voltage: 5000Vrms
• Package Type: PDIP
• Operating Temp Range: -40C to 85C
• Power Dissipation: 85mW
• Propagation Delay Time: 75ns
• Pin Count: 8
• Mounting: Through Hole
• Reverse Breakdown Voltage: 5V
• Operating Temperature Classification: Industrial
• Lead Free Status / Rohs Status: Not Compliant

Electrical Specifications
Over recommended temperature (T
All enable test conditions apply to single channel products only. See note 5.
*JEDEC registered data for the 6N137. The JEDEC Registration specifies 0°C to +70°C. HP specifies -40°C to +85°C.
12
Parameter
High Level Output
Current
Input Threshold
Current
Low Level Output
Voltage
High Level Supply
Current
Low Level Supply
Current
High Level Enable
Current
Low Level Enable
Current
High Level Enable
Voltage
Low Level Enable
Voltage
Input Forward
Voltage
Input Reverse
Breakdown
Voltage
Input Diode
Temperature
Coefficient
Input Capacitance
Sym.
DV
BV
V
I
I
I
V
∆T
I
V
C
OH
I
I
CCH
EL
V
OL
CCL
TH
EH
EH
EL
IN
F
R
*
F
*
A
*
*
/
Single Channel
Single Channel
Single Channel
Single Channel
Dual Channel
Dual Channel
Dual Channel
Widebody
Widebody
Widebody
Widebody
Widebody
Widebody
8-Pin DIP
8-Pin DIP
8-Pin DIP
8-Pin DIP
8-Pin DIP
Package
SO-8
SO-8
SO-8
SO-8
SO-8
All
A
= -40°C to +85°C) unless otherwise specified. All Typicals at V
Min.
1.25
2.0
1.4
1.3
1.2
5
3
0.35
1.64
Typ.
-0.7
-0.9
-1.6
-1.9
5.5
2.0
2.5
0.4
7.0
6.5
9.0
8.5
1.5
10
13
60
70
10.0*
13.0*
1.75*
Max.
1.80
1.85
2.05
100
-1.6
-1.6
5.0
0.6
0.8
15
21
mV/°C
Units
mA
mA
mA
mA
mA
μA
pF
V
V
V
V
V
V
V
V
V
I
V
I
I
V
V
Both
Channels
V
V
Both
Channels
V
V
T
T
I
I
f = 1 MHz, V
I
OL
F
OL
R
R
F
CC
O
CC
A
A
O
CC
E
E
E
E
CC
CC
= 5 mA,
= 10 μA
= 100 μA, T
= 10 mA
= 5.5 V, I
= 25°C
= 25°C
= 0.5 V
= V
= 0.5 V
= V
(Sinking) = 13 mA
(Sinking) = 13 mA
= 0.6 V,
Test Conditions
= 5.5 V, V
= 5.5 V, V
= 5.5 V, V
= 5.5 V, V
= 5.5 V, V
CC
CC
F
E
E
= 250 mA
E
E
F
E
A
= 2.0 V,
= 2.0 V,
I
I
I
= 2.0 V
= 0.5 V
= 0 V
V
V
= 2.0 V,
F
F
F
CC
CC
= 25°C
= 0 mA
= 10 mA
= 10 mA
= 5.5 V
= 5.5 V
CC
= 5 V, T
2, 3,
Fig.
2, 3
4, 5
6, 7
1
7
A
= 25°C.
1, 19
Note
1, 6,
19
19
19
7
8
9
1
1
1
1