UNR911AJ0L Panasonic - SSG, UNR911AJ0L Datasheet - Page 7

• Manufacturer Part Number: UNR911AJ0L
• Description: TRANS PNP 50V 100MA W/RES SSMINI
• Manufacturer: Panasonic - SSG

Specifications of UNR911AJ0L

• Transistor Type: PNP - Pre-Biased
• Current - Collector (ic) (max): 100mA
• Voltage - Collector Emitter Breakdown (max): 50V
• Resistor - Base (r1) (ohms): 100K
• Resistor - Emitter Base (r2) (ohms): 100K
• Dc Current Gain (hfe) (min) @ Ic, Vce: 80 @ 5mA, 10V
• Vce Saturation (max) @ Ib, Ic: 250mV @ 300µA, 10mA
• Current - Collector Cutoff (max): 500nA
• Frequency - Transition: 80MHz
• Power - Max: 125mW
• Mounting Type: Surface Mount
• Package / Case: SS Mini3-F1 (SC 89)
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Other names: UNR911AJ0LTR; UNR911AJTR; UNR911AJTR

Characteristics charts of UNR9115J
Characteristics charts of UNR9116J
−160
−120
−160
−120
−80
−40
−80
−40
−10
0
0
6
5
4
3
2
1
0
0
0
Collector-emitter voltage V
Collector-emitter voltage V
−1
Collector-base voltage V
−2
−2
I
B
= −1.0 mA
C
−4
−4
−1
I
I
I
B
C
ob
C
= −1.0 mA
 V
 V
 V
−6
−6
CE
CE
CB
−10
− 0.9 mA
−8
−8
− 0.9 mA
− 0.8 mA
T
f = 1 MHz
I
T
T
− 0.8 mA
E
a
a
a
− 0.7 mA
− 0.3 mA
− 0.2 mA
− 0.1 mA
CB
− 0.6 mA
− 0.5 mA
− 0.4 mA
= 0
− 0.7 mA
− 0.6 mA
− 0.5 mA
− 0.4 mA
− 0.3 mA
− 0.2 mA
− 0.1 mA
= 25°C
= 25°C
= 25°C
−10
CE
−10
CE
( V )
( V )
( V )
−10
−12
−12
2
−10
−10
−10
−10
−10
−10
−10
−10
−10
−10
−10
−10
−1
−1
−1
−10
−10
−1
−2
−1
−2
−0.4
2
2
4
3
2
−1
−1
Collector current I
−25°C
Collector current I
−0.6
Input voltage V
SJH00038BED
−25°C
V
V
−1
−1
CE(sat)
I
CE(sat)
−0.8
O
25°C
25°C
 V
 I
−1.0
 I
IN
−10
−10
IN
C
C
T
C
C
T
I
a
I
C
( mA )
C
( mA )
( V )
= 75°C
a
V
T
−1.2
/ I
= 75°C
/ I
a
O
= 25˚C
B
B
= −5 V
= 10
= 10
−10
−10
−1.4
2
2
−10
−10
−10
−10
400
300
200
100
400
300
200
100
−1
−10
−1
−2
0
2
0
−1
−1
−1
Collector current I
Collector current I
UNR911xJ Series
Output current I
−10
−10
−1
V
h
h
FE
FE
IN
 I
 I
 I
T
−10
−10
O
−10
T
C
C
a
O
C
a
C
= 75°C
V
T
V
( mA )
V
= 75°C
25°C
−25°C
−25°C
2
2
25°C
O
a
CE
( mA )
CE
( mA )
= 25°C
= − 0.2 V
= −10 V
= −10 V
−10
−10
−10
7
2
3
3