107314676 Lineage Power, 107314676 Datasheet - Page 13

• Manufacturer Part Number: 107314676
• Description: Module DC-DC 1-OUT 15V 3.33A 50W 9-Pin
• Manufacturer: Lineage Power
• Type: Step Downr

Specifications of 107314676

• Output Current: 3.33 A
• Output Voltage: 15 V
• Input Voltage: 28 V
• Number Of Outputs: 1
• Output Power: 50 W

Thermal considerations
Heat Transfer with Heat Sinks
Solution
Given: V
Determine P
Then solve the following equation:
Use Figure 24 to determine air velocity for the0.5 inch
heat sink.
The minimum airflow necessary for the JC100C
module is 1.0 m/s (200 ft./min.).
θ
θ
θ
ca
ca
ca
Data Sheet
March 2008
I
T
T
Heat sink = 0.5 in.
P
Lineage Power
O
=
=
=
A
C
I
D
= 28 V
= 6 A
= 40 °C
= 85 °C
= 14.0 W
3.2
D
(
----------------------- -
(
----------------------- -
T
85 40
by using Figure 23:
°C/W
C
14.0
P
–
–
D
T
A
)
)
(continued)
(continued)
JC050C, JC075C, JC100C Power Modules: dc-dc Converters;
18 Vdc to 36 Vdc Input, 15 Vdc Output; 50 W to 100 W
Custom Heat Sinks
A more detailed model can be used to determine the
required thermal resistance of a heat sink to provide
necessary cooling. The total module resistance can be
separated into a resistance from case-to-sink (θcs) and
sink-to-ambient (θsa) shown below (Figure 25).
Figure 25. Resistance from Case-to-Sink and
For a managed interface using thermal grease or foils,
a value of θcs = 0.1 °C/W to 0.3 °C/W is typical. The
solution for heat sink resistance is:
This equation assumes that all dissipated power must
be shed by the heat sink. Depending on the user-
defined application environment, a more accurate
model, including heat transfer from the sides and bot-
tom of the module, can be used. This equation pro-
vides a conservative estimate for such instances.
Layout Considerations
Copper paths must not be routed beneath the power
module mounting inserts.
θ
sa
P
=
D
→
(
------------------------ -
Sink-to-Ambient
T
C
P
T
–
D
C
T
A
)
–
θcs
θ
cs
T
S
θsa
T
A
8-1304
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