MBR30H100CT ON Semiconductor, MBR30H100CT Datasheet - Page 6

DIODE SCHOTTKY 100V 15A TO-220AB

MBR30H100CT

Manufacturer Part Number
MBR30H100CT
Description
DIODE SCHOTTKY 100V 15A TO-220AB
Manufacturer
ON Semiconductor
Series
SWITCHMODE™r
Datasheet

Specifications of MBR30H100CT

Voltage - Forward (vf) (max) @ If
800mV @ 15A
Current - Reverse Leakage @ Vr
4.5µA @ 100V
Current - Average Rectified (io) (per Diode)
15A
Voltage - Dc Reverse (vr) (max)
100V
Diode Type
Schottky
Speed
Fast Recovery =< 500ns, > 200mA (Io)
Diode Configuration
1 Pair Common Cathode
Mounting Type
Through Hole
Package / Case
TO-220-3 (Straight Leads)
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Reverse Recovery Time (trr)
-

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Figure 13 was used to demonstrate the controlled avalanche
capability of this device. A mercury switch was used instead
of an electronic switch to simulate a noisy environment
when the switch was being opened.
up linearly; and energy is stored in the coil. At t
is opened and the voltage across the diode under test begins
to rise rapidly, due to di/dt effects, when this induced voltage
reaches the breakdown voltage of the diode, it is clamped at
BV
which now starts to decay linearly through the diode, and
goes to zero at t
is opened; and calculating the energy that is transferred to
the diode it can be shown that the total energy transferred is
equal to the energy stored in the inductor plus a finite amount
of energy from the V
breakdown (from t
component resistances. Assuming the component resistive
The unclamped inductive switching circuit shown in
When S
By solving the loop equation at the point in time when S
DUT
and the diode begins to conduct the full load current
1
MERCURY
SWITCH
is closed at t
2
S
.
1
Figure 13. Test Circuit
1
DD
to t
0
power supply while the diode is in
the current in the inductor I
2
I
) minus any losses due to finite
L
+V
10 mH COIL
DUT
DD
I
D
1
V
the switch
D
L
http://onsemi.com
ramps
1
6
elements are small Equation (1) approximates the total
energy transferred to the diode. It can be seen from this
equation that if the V
breakdown voltage of the device, the amount of energy
contributed by the supply during breakdown is small and the
total energy can be assumed to be nearly equal to the energy
stored in the coil during the time when S
Equation (2).
W
t
W
EQUATION (1):
EQUATION (2):
0
AVAL
AVAL
Figure 14. Current−Voltage Waveforms
[ 1
[ 1
2
2
I
LI
LI
L
2
LPK
2
LPK
DD
voltage is low compared to the
BV
BV
DUT
DUT
t
1
V
DD
BV
DUT
I
D
1
was closed,
t
2
V
DD
t

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