25CTQ045 Vishay, 25CTQ045 Datasheet - Page 3

• Manufacturer Part Number: 25CTQ045
• Description: DIODE SCHOTTKY 45V 15A TO-220AB
• Manufacturer: Vishay

Specifications of 25CTQ045

• Voltage - Forward (vf) (max) @ If: 710mV @ 30A
• Current - Reverse Leakage @ Vr: 1.75mA @ 45V
• Current - Average Rectified (io) (per Diode): 15A
• Voltage - Dc Reverse (vr) (max): 45V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Through Hole
• Package / Case: TO-220-3 (Straight Leads)
• Product: Schottky Rectifiers
• Peak Reverse Voltage: 45 V
• Forward Continuous Current: 30 A
• Max Surge Current: 990 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.71 V
• Maximum Reverse Leakage Current: 1750 uA
• Operating Temperature Range: - 55 C to + 150 C
• Mounting Style: Through Hole
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant, Lead free / RoHS Compliant
• Other names: *25CTQ045; VS-25CTQ045; VS-25CTQ045; VS25CTQ045; VS25CTQ045

Document Number: 93291
Revision: 22-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
1000
100
0.1
10
1
0
0.001
0.2
0.01
0.1
10
0.00001
V
1
FM
0.4
- Forward Voltage Drop (V)
0.6
0.8
(Per Leg)
0.0001
1.0
T
T
T
J
J
J
Fig. 4 - Maximum Thermal Impedance Z
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
1.2
= 150 °C
= 125 °C
= 25 °C
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(thermal resistance)
1.4
Single pulse
1000
Schottky Rectifier, 2 x 15 A
100
1.6
0.001
0
1.8
t
1
2.0
- Rectangular Pulse Duration (s)
10
V
R
- Reverse Voltage (V)
0.01
T
J
20
= 25 °C
D = 0.50
D = 0.33
D = 0.25
D = 0.17
D = 0.08
30
thJC
0.1
Characteristics (Per Leg)
0.001
1000
0.01
100
0.1
10
40
1
0
Fig. 2 - Typical Values of Reverse Current vs.
Vishay High Power Products
T
5
J
T
50
1
T
= 150 °C
J
J
= 125 °C
T
Notes:
1. Duty factor D = t
2. Peak T
10
= 100 °C
V
J
Reverse Voltage (Per Leg)
T
= 75 °C
R
J
- Reverse Voltage (V)
= 50 °C
15
T
J
J
= 25 °C
P
25CTQ... Series
= P
DM
20
10
DM
t
1
25
x Z
t
2
1
/t
thJC
2
30
+ T
C
35
100
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40
45
3