AD9517-2BCPZ Analog Devices Inc, AD9517-2BCPZ Datasheet - Page 44
![IC,Twelve Distributed-Output Clock Driver,LLCC,48PIN,PLASTIC](/photos/6/50/65022/cp-48-8_sml.jpg)
AD9517-2BCPZ
Manufacturer Part Number
AD9517-2BCPZ
Description
IC,Twelve Distributed-Output Clock Driver,LLCC,48PIN,PLASTIC
Manufacturer
Analog Devices Inc
Type
Clock Generator, Fanout Distributionr
Datasheet
1.AD9517-2ABCPZ-RL7.pdf
(80 pages)
Specifications of AD9517-2BCPZ
Pll
Yes
Input
CMOS, LVDS, LVPECL
Output
CMOS, LVDS, LVPECL
Number Of Circuits
1
Ratio - Input:output
1:12
Differential - Input:output
Yes/Yes
Frequency - Max
2.33GHz
Divider/multiplier
Yes/No
Voltage - Supply
3.135 V ~ 3.465 V
Operating Temperature
-40°C ~ 85°C
Mounting Type
Surface Mount
Package / Case
48-LFCSP
Frequency-max
2.33GHz
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
For Use With
AD9517-2/PCBZ - BOARD EVAL FOR AD9517-2
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
AD9517-2
Duty Cycle and Duty-Cycle Correction (Divider 2 and
Divider 3)
The same duty cycle and DCC considerations apply to Divider 2
and Divider 3 as to Divider 0 and Divider 1 (see the Duty Cycle
and Duty-Cycle Correction (0, 1) section); however, with these
channel dividers, the number of possible configurations is even
more complex.
Duty-cycle correction on Divider 2 and Divider 3 requires the
following channel divider conditions:
•
•
•
•
The possibilities for the duty cycle of the output clock from
Divider 2 and Divider 3 are shown in Table 40 through Table 44.
Table 40. Divider 2 and Divider 3 Duty Cycle; VCO Divider
Used; Duty Cycle Correction Off (DCCOFF = 1)
VCO
Divider
Even
Odd = 3
Odd = 5
Even
Odd
Even
Odd
Table 41. Divider 2 and Divider 3 Duty Cycle; VCO Divider
Not Used; Duty Cycle Correction Off (DCCOFF = 1)
Input Clock
Duty Cycle
50%
X%
50%
X%
50%
X%
An even D
cycles).
An odd D
low cycles must be one greater than the number of high
cycles).
If only one divider is bypassed, it must be the second
divider, X.2.
If only one divider has an even divide-by, it must be the
second divider, X.2.
X.Y
X.Y
N
1
1
1
Even, odd
Even, odd
Even, odd
Even, odd
N
1
1
Even, odd
Even, odd
Even, odd
Even, odd
X.1
X.1
must be set as M
must be set as M
+ M
+ M
D
D
X.1
X.1
X.1
X.1
+ 2
+ 2
N
1
1
1
1
1
Even, odd
Even, odd
N
1
1
1
1
Even, odd
Even, odd
X.2
X.2
X.Y
X.Y
+ M
+ M
= N
D
D
= N
X.2
X.2
X.2
X.2
X.Y
X.Y
+ 2
+ 2
+ 1 (the number of
(low cycles = high
Output
Duty Cycle
50%
33.3%
40%
(N
(N
(N
(N
(N
(N
(N
(N
Output
Duty Cycle
50%
X%
(N
(N
(N
(N
(N
(N
(N
(N
X.1
X.1
X.1
X.1
X.2
X.2
X.2
X.2
X.1
X.1
X.1
X.1
X.2
X.2
X.2
X.2
+ 1)/
+ M
+ 1)/
+ M
+ 1)/
+ M
+ 1)/
+ M
+ 1)/
+ M
+ 1)/
+ M
+ 1)/
+ M
+ 1)/
+ M
X.1
X.1
X.2
X.2
X.1
X.1
X.2
X.2
+ 2)
+ 2)
+ 2)
+ 2)
+ 2)
+ 2)
+ 2)
+ 2)
Rev. B | Page 44 of 80
Table 42. Divider 2 and Divider 3 Duty Cycle; VCO Divider
Used; Duty Cycle Correction Is On (DCCOFF = 0); VCO
Divider Input Duty Cycle = 50%
VCO
Divider
Even
Odd
Even
Odd
Even
Odd
Even
Odd
Even
Odd
Even
Odd
Table 43. Divider 2 and Divider 3 Duty Cycle; VCO Divider
Used; Duty Cycle Correction On (DCCOFF = 0); VCO
Divider Input Duty Cycle = X%
VCO
Divider
Even
Odd = 3
Odd = 5
Even
Odd
Even
Odd = 3
Odd = 5
Even
Odd
Even
Odd
Even
Odd = 3
Odd = 5
1
1
Even (N
Even (N
N
Even (N
Odd (M
Odd (M
Even (N
Odd (M
Odd (M
Odd (M
Odd (M
N
1
1
1
Even
(N
Even
(N
Odd
(M
Odd
(M
Odd
(M
Even
(N
Even
(N
Odd
(M
Odd
(M
Odd
(M
Odd
(M
Odd
(M
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
+ M
+ M
= M
= M
= N
= N
= N
= M
= M
= N
= N
= N
= N
= N
D
X.1
X.1
X.1
X.1
X.1
X.1
X.1
D
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
= N
= N
= N
= N
= N
= N
= M
= M
= M
= M
+ 1)
+ 1)
+ 1)
+ 1)
+ 1)
+ 1)
+ 1)
+ 1)
)
)
)
)
+ 2
+ 2
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
X.1
+ 1)
+ 1)
+ 1)
+ 1)
+ 1)
+ 1)
)
)
)
)
N
1
1
1
1
1
1
1
1
Even
(N
Even
(N
Even
(N
Even
(N
Odd
(M
Odd
(M
Odd
(M
X.2
X.2
X.2
X.2
X.2
X.2
X.2
X.2
+ M
N
1
1
1
1
1
1
Even (N
Even (N
Even (N
Even (N
Odd (M
Odd (M
= M
= M
= M
= M
= N
= N
= N
D
X.2
X.2
X.2
X.2
X.2
X.2
+ M
X.2
X.2
X.2
X.2
+ 1)
+ 1)
+ 1)
)
)
)
)
+ 2
X.2
X.2
D
X.2
X.2
X.2
X.2
X.2
X.2
= N
= N
= M
= M
= M
= M
+ 2
X.2
X.2
Output
Duty Cycle
50%
(1 + X%)/3
(2 + X%)/5
50%
50%
50%
(3N
(6N
(5N
(10N
50%
50%
50%
50%
50%
(6N
9N
(3(2N
(2N
(10N
15N
(5(2 N
(2 N
X.2
X.2
X.2
X.2
+ 1)
+ 1)
)
)
)
)
X.2
X.1
X.1
X.1
X.1
X.2
X.2
X.2
X.1
X.1
N
+ 13 + X%)/
X.1
+ 4 + X%)/
+ 9)
+ 7 + X%)/
+ 3))
X.1
N
+ 22 + X%)/
+ 3))
X.2
+ 15)
X.2
+ 3)
Output
Duty Cycle
50%
50%
50%
50%
50%
50%
50%
50%
50%
50%
50%
50%
+ 3)
+ 9N
+ 15N
X.1
X.1
+
+