ACPL-224-500E Avago Technologies US Inc., ACPL-224-500E Datasheet - Page 5

• Manufacturer Part Number: ACPL-224-500E
• Description: AC Phototx Coupler Dual, L/F+ T/R
• Manufacturer: Avago Technologies US Inc.

Specifications of ACPL-224-500E

• Number Of Channels: 2
• Input Type: AC, DC
• Voltage - Isolation: 3000Vrms
• Current Transfer Ratio (min): 20% @ ±1mA
• Current Transfer Ratio (max): 400% @ ±1mA
• Voltage - Output: 80V
• Current - Output / Channel: 50mA
• Current - Dc Forward (if): ±50mA
• Vce Saturation (max): 400mV
• Output Type: Transistor
• Mounting Type: Surface Mount
• Package / Case: SO-8
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

Electrical Specifications (DC)
Over recommended ambient temperature at 25°C unless otherwise specified.
Figure 1. Switching Time Test Circuit
5
Parameter
Forward Voltage
Reverse Current
Terminal Capacitance
Collector Dark Current
Collector-Emitter
Breakdown Voltage
Emitter-Collector
Breakdown Voltage
Current Transfer Ratio
Saturated CTR
Collector-Emitter
Saturation Voltage
Isolation Resistance
Floating Capacitance
Cut-off Frequency (-3dB)
Response Time (Rise)
Response Time (Fall)
Turn-on Time
Turn-off Time
Turn-ON Time
Storage Time
Turn-OFF Time
Common Mode
Rejection Voltage
Symbol
V
I
C
I
BV
BV
CTR
CTR(sat)
V
R
C
F
t
t
t
t
t
T
t
CMR
R
CEO
r
f
on
off
ON
OFF
C
S
F
CE
iso
t
F
CEO
ECO
(sat)
Min.
-
-
-
-
80
7
20
-
-
5x10
-
-
-
-
-
-
-
-
-
-
10
Typ.
1.2
-
30
-
-
-
-
60
-
1x10
0.6
80
2
3
3
3
2
25
40
10
11
Max.
1.4
10
-
100
-
-
400
-
0.4
-
1
-
-
-
-
-
-
-
-
-
Units
V
μA
pF
nA
V
V
%
%
V
Ω
pF
kHz
μs
μs
μs
μs
μs
μs
μs
kV/μs
Test Conditions
I
V
V = 0, f = 1MHz
V
I
I
I
I
I
DC500V, R.H. 40~60%
V = 0, f = 1MHz
V
R
V
R
V
R
T
V
V
F
C
E
F
F
F
a
R
CE
CC
L
CC
L
CC
L
CM
CC
=±1mA, V
Figure 2. Frequency Response Test Circuit
= ±20mA
= ±1 mA, V
= ±8mA, I
=25ºC, R
= 100 μA, I
= 0.5 mA, I
= 100Ω
= 100Ω
= 1.9kΩ
= 5V
=9V, V
= 48V, I
= 5V, I
= 10V, I
= 5V, I
=1.5kV(peak), I
np
C
F
L
F
CE
C
=470Ω,
= ±16 mA,
= 2 mA,
C
=100mV
= 0 mA
F
F
CE
= 2 mA,
= 2.4mA
= 0 mA
= 0.4V
= 0 mA
= 5V
F
=0mA,
Note
Fig.6
Fig.12
CTR=(I
Fig.14
Fig. 2,19
Fig. 1
Fig. 1, 17
Fig.20
C
/I
F
)* 100%