ACPL-217-50CE Avago Technologies US Inc., ACPL-217-50CE Datasheet - Page 4
ACPL-217-50CE
Manufacturer Part Number
ACPL-217-50CE
Description
Phototx Coupler Single, LF+T/R
Manufacturer
Avago Technologies US Inc.
Datasheet
1.ACPL-217-500E.pdf
(7 pages)
Specifications of ACPL-217-50CE
Number Of Channels
1
Input Type
DC
Voltage - Isolation
3000Vrms
Current Transfer Ratio (min)
200% @ 5mA
Current Transfer Ratio (max)
400% @ 5mA
Voltage - Output
80V
Current - Output / Channel
50mA
Current - Dc Forward (if)
50mA
Vce Saturation (max)
400mV
Output Type
Transistor
Mounting Type
Surface Mount
Package / Case
SO-4
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Electrical Specifications (DC)
Over recommended ambient temperature at 25ºC unless otherwise specified.
Figure 1. Switching Time Test Circuit
Figure 2. Frequency Response Test Circuit
4
I
Parameter
Forward Voltage
Reverse Current
Terminal Capacitance
Collector Dark Current
Collector-Emitter Breakdown Voltage
Emitter-Collector Breakdown Voltage
Current Transfer Ratio
Saturated CTR
Collector-Emitter Saturation Voltage
Isolation Resistance
Floating Capacitance
Cut-off Frequency (-3dB)
Response Time (Rise)
Response Time (Fall)
Turn-on Time
Turn-off Time
Turn-ON Time
Storage Time
Turn-OFF Time
Common Mode Rejection Voltage
F
R
D
R
L
V
V
CC
CE
R
L
Output
V
V
I
I
CE
CE
V
F
F
CC
Symbol
V
I
C
I
BV
BV
CTR
CTR(sat)
V
R
C
F
t
t
t
t
t
T
t
CMR
R
CEO
r
f
on
off
ON
OFF
C
S
F
t
CE
ISO
F
CEO
ECO
(sat)
t
t
on
on
Min.
-
-
-
-
80
7
50
-
-
5x10
-
-
-
-
-
-
-
-
-
-
t
t
r
r
10
t
t
t
t
t
t
f
f
s
s
off
off
Typ.
1.2
-
30
-
-
-
-
100
-
1x10
0.6
80
2
3
3
3
2
25
40
10
90%
90%
10%
10%
11
Max.
1.4
10
-
100
-
-
600
-
0.4
-
1
-
-
-
-
-
-
-
-
-
Units
V
PA
pF
nA
V
V
%
V
:
pF
kHz
Ps
Ps
Ps
Ps
Ps
Ps
Ps
kV/Ps
%
Test Conditions
I
V
V = 0, f = 1MHz
V
I
I
I
I
I
DC500V, R.H. 40~60%
V = 0, f = 1MHz
V
R
V
R
V
R
Ta=25ºC, R
V
I
V
F
C
E
F
F
F
F
R
CE
CC
L
CC
L
CC
L
CM
np
=1mA, V
=0mA, V
= 20mA
= 100 PA, I
= 5 mA, V
= 8mA, I
= 0.5 mA, I
= 100:
= 100:
= 1.9k:
= 5V
=100mV
= 48V, I
= 5V, I
= 10V, I
= 5V, I
=1.5kV(peak),
CE
CC
C
F
C
L
F
C
CE
= 16 mA,
= 2 mA,
=470:,
= 2.4mA
=9V,
= 0.4V
= 0 mA
F
F
= 2 mA,
= 5V
= 0 mA
= 0 mA
Note
Fig.6
Fig.12
CTR=(I
100%
Fig.14
Fig. 2,19
Fig. 1
Fig. 1, 17
Fig.20
C
/IF )*