01300 Simpson, 01300 Datasheet - Page 64
![Analog Panel Meters CUR XFMR DONUT 300/5](/photos/18/5/180569/donut-pmaccess_sml.jpg)
01300
Manufacturer Part Number
01300
Description
Analog Panel Meters CUR XFMR DONUT 300/5
Manufacturer
Simpson
Type
Inductiver
Specifications of 01300
Dimensions
27.94 mm W
Number Of Outputs
1
Primary Voltage Rating
300 V
Secondary Voltage Rating
5 V
Termination Style
Round Crimp Terminals
Accuracy
0.6 %
Current, Primary
300 A
Current, Ratio
300:5
Current, Secondary
5 A
Diameter, Inside
2.06 in.
Diameter, Outside
3.56 in.
Frequency Response
50 to 400 Hz
Function
Current
Material, Stud
Brass
Primary Type
Current
Range, Measurement
300 A
Standards
UL and CSA Approved
Technology
Inductive
Thickness
1.1 in.
Transformer Type
Donut
Turns Ratio
60:1
Input Current
300A
Transformer Mounting
Panel
Current Ratio
300
Leaded Process Compatible
No
Mounting Type
Donut
Output Current
5A
Peak Reflow Compatible (260 C)
No
Power Rating
2VA
Rohs Compliant
No
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
For Use With
The primary wire passing through the core, or by wrapping the secondary wires leading to the meter
Formula:
Where:
The ratio of the current transformer can be modified by adding
more primary turns to the transformer. By adding primary
turns, the current required to maintain five amps on the sec-
ondary is reduced.
Example:
1 Primary Turn
2 Primary Turns
4 Primary Turns
Donut Current Transformer Wrapping Information
Donut Current Transformer Wrapping Information
Nameplate
Nameplate
Nameplate
Primary Turn Ratio Modification
100:5
100:5
100:5
Ratio
Ratio
Ratio
A 100:5 current transformer designed for one
primary turn.
Ka = Kn x Nn / Na
Ka = Actual Transformer Ratio
Kn = Nameplate Transformer Ratio
Na = Actual Number of Primary Turns
Nn = Nameplate Number of Primary Turns
Actual
Actual
Actual
Ratio
100:5
Ratio
Ratio
50:5
25:5
Formula:
Where:
Example:
(In practicality one turn is dropped from the secondary as a ratio correc-
tion factor.)
The ratio of the current transformer can be modified by altering the
number of secondary turns by forward or backwinding the secondary
lead through the window of the current transformer. By adding second-
ary turns, the same primary current will result in a decrease in second-
ary output. By subtracting turns, the same primary current will result in
greater secondary output.
Again using the 300:5 example adding five secondary turns will require
325 amps on the primary to maintain the 5 amp secondary output or
Deducting 5 secondary turns will only require 275 amps on the primary
to maintain the 5 amp secondary output or
The above ratio modifications are achieved in the following manner:
Primary Turn Ratio Modification
lp
ls
lp - Primary Current
ls - Secondary Current
Np - Number of Primary Turns
Ns - Number of Secondary Turns
A 300:5 Current Transformer.
300p
325p
325p
5s
5s
5s
Ns
Np
60s
1p
65s
1p
65s
1p