AD8031AR Analog Devices Inc, AD8031AR Datasheet - Page 10

• Manufacturer Part Number: AD8031AR
• Description: IC OPAMP VF R-R LP LDIST 8SOIC
• Manufacturer: Analog Devices Inc

Specifications of AD8031AR

• Slew Rate: 35 V/µs
• Mounting Type: Surface Mount
• Package / Case: 8-SOIC (3.9mm Width)
• Rohs Status: RoHS non-compliant
• Design Resources: High Speed, Precision, Differential AC-Coupled Drive Circuit for AD7625 (CN0080) Single-Ended-to-Differential High Speed Drive Circuit for 16-Bit, 10 MSPS AD7626 ADC (CN0105)
• Amplifier Type: Voltage Feedback
• Number Of Circuits: 1
• Output Type: Rail-to-Rail
• -3db Bandwidth: 80MHz
• Current - Input Bias: 450nA
• Voltage - Input Offset: 1000µV
• Current - Supply: 900µA
• Current - Output / Channel: 15mA
• Voltage - Supply, Single/dual (±): 2.7 V ~ 12 V, ±1.35 V ~ 6 V
• Operating Temperature: -40°C ~ 85°C
• No. Of Amplifiers: 1
• Bandwidth: 80MHz
• No. Of Pins: 8
• Peak Reflow Compatible (260 C): No
• Leaded Process Compatible: No
• Gain Bandwidth Product: -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant

AD8031/AD8032
–1
–2
–3
–4
–5
–1
–2
–3
–4
–5
–1
–2
–3
–4
–5
–6
–7
–8
100k
5
4
3
2
1
0
3
2
1
0
2
1
0
V
IN
Figure 28. Closed-Loop Gain vs. Supply Voltage
Figure 27. Closed-Loop Gain vs. Temperature
Figure 26. Unity Gain, −3 dB Bandwidth
0.1
0.1
V
V
S
IN
V
S
= 5V
= –16dBm
1M
2kΩ
G = +1
C
R
FREQUENCY (MHz)
FREQUENCY (MHz)
R
L
L
FREQUENCY (Hz)
L
= 5pF
= 1kΩ
+ C
1
1
50Ω
L
V
S
V
TO 1.35V
OUT
= +2.7V
10M
+85°C
+25°C
V
10
10
S
V
G = +1
R
= ±5V
–40°C
S
L
= 5V
= 1kΩ
V
R
TO 2.5V
S
100M
L
100
100
= +5V
+ C
L
Rev. D | Page 10 of 20
–135
–180
–225
–90
–100
–20
–30
–40
–50
–60
–70
–80
–20
–30
–40
–50
–60
–70
–80
–90
0.3
Figure 30. Total Harmonic Distortion vs. Frequency; G = +1
Figure 31. Total Harmonic Distortion vs. Frequency; G +2
1k
1k
G = +1, R
Figure 29. Open-Loop Frequency Response
G = +2
V
R
S
L
1
= 5V
= 1kΩ TO
PHASE
4.8V p-p
L
FUNDAMENTAL FREQUENCY (Hz)
FUNDAMENTAL FREQUENCY (Hz)
10k
10k
= 2kΩ TO
V
FREQUENCY (MHz)
2.5V p-p
V
S
GAIN
CC
2
= 2.7V
4.6V p-p
V
CC
2
100k
100k
10
V
4.8V p-p
V
1.3V p-p
S
S
= 2.7V
= 5V
4V p-p
1M
1M
2V p-p
V
S
100
= 2.7V
1V p-p
10M
10M
40
30
20
10
0
–10
–20