LM359M National Semiconductor, LM359M Datasheet - Page 13
LM359M
Manufacturer Part Number
LM359M
Description
IC AMP DUAL PROG CUR MODE 14SOIC
Manufacturer
National Semiconductor
Datasheet
1.LM359M.pdf
(26 pages)
Specifications of LM359M
Amplifier Type
General Purpose
Number Of Circuits
2
Slew Rate
60 V/µs
Gain Bandwidth Product
400MHz
Current - Input Bias
8µA
Current - Supply
18.5mA
Current - Output / Channel
40mA
Voltage - Supply, Single/dual (±)
5 V ~ 22 V, ±2.5 V ~ 11 V
Operating Temperature
0°C ~ 70°C
Mounting Type
Surface Mount
Package / Case
14-SOIC (3.9mm Width), 14-SOL
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Output Type
-
-3db Bandwidth
-
Voltage - Input Offset
-
Other names
*LM359M
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Application Hints
DESIGN EXAMPLE
e
BW = 20 MHz, A
V
1. Basic circuit configuration:
2. Select I
3. Since the closed loop bandwidth will be determined by
IN
+
= 12V.
= 50 mV (MAX), f
that the closed loop bandwidth will be determined by R
and C
amplifier open loop gain of at least 20 dB at the desired
closed loop bandwidth of the circuit. For this example,
an I
20 MHz which will be sufficient. Using single resistor
programming for I
to obtain a 20 MHz bandwidth, both R
kept small. It can be assumed that C
of 1 pF to 5 pF for carefully constructed circuit boards to
insure stability and allow a flat frequency response. This
will limit the value of R
Also, for a closed loop gain of +10, R
R
s
+ r
SET
e
f
. To do this, the set current should program an
SET
of 0.5 mA will provide 26 dB of open loop gain at
where r
to provide adequate amplifier bandwidth so
V
= 20 dB, driving source impedance = 75Ω,
e
is the mirror diode resistance.
SET
IN
:
= 10 MHz (MAX), desired circuit
f
to be within the range of:
(Continued)
f
can be in the range
f
f
must be 10 times
and C
f
should be
00778820
f
13
4. So as not to appreciably load the 75Ω input termination
5. For A
6. The optimum output DC level for symmetrical AC swing
7. The DC feedback current must be:
8. R
9. Since R
10. As a final design step, C
resistance the value of (R
is:
DC biasing predictability will be insured because 640 µA
is greater than the minimum of I
For gain accuracy the total AC and DC mirror current
should be less than 2 mA. For this example the maxi-
mum AC mirror current will be:
therefore the total mirror current range will be 574 µA to
706 µA which will insure gain accuracy.
mirror current to be:
R
resistor in series with a 30Ω resistor which are standard
5% tolerance resistor values.
lower passband frequency corner of 8 Hz for this ex-
ample.
A larger value may be used and a 0.01 µF ceramic
capacitor in parallel with C
gain accuracy.
b
s
can now be found:
must be 750Ω–40Ω or 710Ω which can be a 680Ω
v
= 10; R
s
+ r
e
f
will be 750Ω and r
is set to 7.5 kΩ.
i
s
must be selected to pass the
i
+ r
will maintain high frequency
e
) is set to 750Ω.
SET
e
/5 or 100 µA.
is fixed by the DC
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