OP77FJZ Analog Devices Inc, OP77FJZ Datasheet - Page 11

• Manufacturer Part Number: OP77FJZ
• Description: IC OPAMP GP 600KHZ PREC TO99-8
• Manufacturer: Analog Devices Inc

Specifications of OP77FJZ

• Slew Rate: 0.3 V/µs
• Amplifier Type: General Purpose
• Number Of Circuits: 1
• Gain Bandwidth Product: 600kHz
• Current - Input Bias: 1.2nA
• Voltage - Input Offset: 20µV
• Voltage - Supply, Single/dual (±): ±3 V ~ 18 V
• Operating Temperature: -25°C ~ 85°C
• Mounting Type: Through Hole
• Package / Case: TO-99-8, Metal Can
• Op Amp Type: Low Offset Voltage
• No. Of Amplifiers: 1
• Bandwidth: 600kHz
• Supply Voltage Range: ± 3V To ± 18V
• Amplifier Case Style: TO-99
• No. Of Pins: 8
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Current - Supply: -
• Output Type: -
• Current - Output / Channel: -
• -3db Bandwidth: -
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant, Lead free / RoHS Compliant

APPLICATIONS
The high gain, gain linearity, CMRR, and low TCV
OP77 make it possible to obtain performance not previously
available in single-stage, very high-gain amplifier applications.
For best CMR,
10 mV differential signal, the maximum errors are as listed in
Table 7.
Table 7. Maximum Errors
Type
Common-Mode Voltage
Gain Linearity, Worst Case
TCV
TCI
This circuit reduces maximum slew rate but allows driving
capacitive loads of any size without instability. Because the boon
resistor is inside the feedback loop, its effect on output
impedance is reduced to insignificance by the high open-loop
gain of the OP77.
OS
OS
INPUT
Figure 27. Precision High-Gain Differential Amplifier
V
IN
Figure 28. Isolating Large Capacitive Loads
R
100kΩ
100kΩ
R
R
S
R1
R2
1
2
1kΩ
1kΩ
Figure 29. Basic Current Source
R1
R3
must equal
10µF
2
3
2
3
OP77
+15V
–15V
OP77
R4
1MΩ
2
3
4
7
0.1µF
0.1µF
OP77E
990Ω
R
1kΩ
R3
R4
+15V
–15V
F
1MΩ
6
R2
7
4
R
R
0.1µF
0.1µF
6
3
4
. In this example, with a
6
100Ω
R5
10Ω
I
OUT
Amount
0.01%/V
0.02%
0.003%/°C
0.008%/°C
< 15mA
C
LOAD
OUTPUT
OS
of the
Rev. E | Page 11 of 16
These current sources can supply both positive and negative
current into a grounded load.
Note that
And that for Z
V
IN
Z
O
=
R1
R2
R
R
5
5
R
⎛
⎜
⎝
O
+
2
3
2
R
R
to be infinite
R
4
2
OP77
Figure 30. 100 mA Current Source
4
I
GIVEN R3 = R4 + R5, R1 = R2
OUT
+
R
R
1
3
1
⎞
⎟
⎠
= V
IN
6
(
R3
R4
R1 – R5
R3
R +
5
R
)
2
+15V
–15V
R
2N2222
2N2907
4
must =
R5
I
OUT
R
R
3
1
< 100mA
OP77