MAX9260GCB/V+GG4 Maxim Integrated, MAX9260GCB/V+GG4 Datasheet - Page 15

• Manufacturer Part Number: MAX9260GCB/V+GG4
• Description: Serializers & Deserializers - Serdes Multimedia Serial Link
• Manufacturer: Maxim Integrated
• Type: Deserializerr

Specifications of MAX9260GCB/V+GG4

• Rohs: yes
• Data Rate: 2.5 Gbit/s
• Input Type: CML
• Output Type: CMOS/LVCMOS
• Number Of Inputs: 1
• Number Of Outputs: 30
• Operating Supply Voltage: 1.7 V to 3.6 V
• Operating Temperature Range: - 40 C to + 105 C
• Package / Case: TQFP-64 EP
• Maximum Operating Temperature: + 105 C
• Minimum Operating Temperature: - 40 C
• Mounting Style: SMD/SMT

amplifier transconductance, which is 900FS (typ), and
R
A dominant pole (f
tion capacitor (C
(R
resistor (R
There is an optional pole (f
cancel the output capacitor ESR zero if it occurs near
the crossover frequency (f
1 (0dB)). Thus:
The loop-gain crossover frequency (f
below 1/5th of the switching frequency and much higher
than the power-modulator pole (f
The total loop gain as the product of the modulator gain,
the feedback voltage-divider gain, and the error-amplifier
gain at f
Forthecasewheref
Therefore:
Solving for R
OUT,EA
OUT,EA
C
GAIN
GAIN
is the output resistance of the error amplifier.
GAIN
). A zero (f
should be equal to 1. So:
C
f
R
dpEA
) and the compensation capacitor (C
C
C
MOD(fC)
:
MOD(fC)
MOD(fC)
GAIN
=
C
g
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=
f
f
m,EA
) and the amplifier output resistance
zEA
pEA
f
pMOD
2
EA(fC)
π ×
dpEA
zEA
zMOD
=
×
=
×
=
×
C
GAIN
V
V
2
) is set by the compensation
2
V
V
C
<<
V
OUT
) is set by the compensa-
C
π ×
OUT
π ×
FB
FB
FB
isgreaterthanf
= g
, where the loop gain equals
×
V
pEA
f
(R
C
OUT
C
×
C
MOD(DC)
m,EA
1
1
×
GAIN
×
C
F
1
OUT,EA
≤
) set by C
pMOD
GAIN
g
×
×
f
SW
m,EA
R
R
5
C
× R
C
MOD(fC)
EA(fC)
36V, 2.2MHz Step-Down Converter
C
):
×
×
+
C
) should be set
R
R )
f
pMOD
C
C
f
F
C
=
=
C
and R
1
1
:
C
with Low Operating Current
C
to
).
Set the error-amplifier compensation zero formed by R
and C
as follows:
If f
C
formed by R
value of C
As the load current decreases, the modulator pole
also decreases; however, the modulator gain increases
accordingly and the crossover frequency remains the
same.
Forthecasewheref
The power-modulator gain at f
The error-amplifier gain at f
Therefore:
Solving for R
Set the error-amplifier compensation zero formed by R
and C
If f
from COMP to GND. Set f
as follows:
F
, from COMP to GND and set the compensation pole
zMOD
zMOD
GAIN
C
C
R
at the f
GAIN
(f
C
is less than 5 x f
is less than 5 x f
zEA
F
MOD(fC)
=
GAIN
as follows:
C
C
g
) at the f
MOD(fC)
:
m,EA
and C
pMOD
EA(fC)
C
C
C
C
C
C
F
×
F
×
V
F
=
=
=
V
=
V
zMOD
(f
OUT
FB
pMOD
(f
=
2
2
2
2
FB
zEA
=
pEA
π ×
π ×
π ×
π ×
GAIN
g
×
C
pEA
V
m,EA
GAIN
×
C
OUT
, add a second capacitor C
f
f
= f
f
f
islessthanf
C
) at the f
pMOD
zMOD
pMOD
zMOD
. Calculate the value of C
g
, add a second capacitor,
is:
MOD(DC)
m,EA
pMOD
C
1
= f
1
1
1
×
MAX16907
×
is:
MOD(fC)
R
zMOD
f
×
×
C
×
×
C
×
R
R
R
R
) as follows:
zMOD
R
×
C
C
C
C
C
f
zMOD
×
and calculate C
×
f
×
f
f
C
pMOD
zMOD
C
. Calculate the
f
f
zMOD
zMOD
:
f
C
=
1
C
C
C
F
F