2sa2094 ROHM Co. Ltd., 2sa2094 Datasheet - Page 2

• Manufacturer Part Number: 2sa2094
• Description: Medium Power Transistor -60v, -2a
• Manufacturer: ROHM Co. Ltd.

Transistors
! ! ! ! Electrical characteristics (Ta=25°C)
! ! ! ! h
! ! ! ! Electrical characteristic curves
∗1 Non repetitive pulse
∗2 See Switching charactaristics measurement circuits
Collector-emitter breakdown voltage
Collector-base breakdown voltage
Emitter-base breakdown voltage
Collector cut-off current
Emitter cut-off current
Collector-emitter saturation voltage
DC current gain
Transition frequency
Corrector output capacitance
Turn-on time
Storage time
Fall time
−0.001
1000
−0.01
100
−0.1
−10
FE
10
−1
−0.001
1
−0.1
COLLECTOR TO EMITTER VOLTAGE : V
120−270
RANK
Single
non repetitive
Pulsed
Fig.4 DC Current Gain vs.
Fig.1 Safe Operating Area
COLLECTOR CURRENT : I
Q
Parameter
−0.01
Collector Current
DC
−1
100ms
10ms
1ms
−0.1
V
V
V
CE
CE
CE
=5V
=3V
=2V
−10
−1
Ta=25°C
C
(ΙΙ)
(A)
CE
−100
−10
(V)
Symbol
V
BV
BV
BV
Tstg
Cob
I
I
CE (sat)
Ton
h
CBO
EBO
Tf
f
FE
CEO
CBO
T
EBO
1000
−0.01
−0.1
100
−10
10
Fig.5 Collector-Emitter Saturation
−1
−0.001
−0.01
−60
−60
120
Min.
−6
−
−
−
−
−
−
−
−
COLLECTOR CURRENT : I
Voltage vs. Collector Current
COLLECTOR CURRENT : I
Fig.2 Switching Time
−0.01
Ta=125°C
Ta=25°C
Ta= −40°C
Tstg
Ton
−200
Typ.
300
100
Tf
−0.1
25
25
30
−
−
−
−
−
−
−0.1
−500
−1.0
−1.0
Max.
270
−
−
−
−
−
−
−
−
−1
Ta=25°C
V
I
I
C
C
CC
−1
/ I
/ I
= −25V
B
B
C
C
=10 / 1
=10 / 1
(A)
(A)
MHz
Unit
mV
µA
µA
pF
ns
ns
ns
V
V
V
−
−10
(Ι)
−10
I
I
I
V
V
I
I
V
I
V
I
f=10MHz
V
I
f=1MHz
I
I
I
V
C
C
E
C
B
C
E
E
C
B1
B2
CB
EB
CE
CE
CB
CC
= −1mA
= −100µA
= −100µA
= −1A
= −0.1A
= −100mA
=100mA
=0mA
= −2A
= −200mA
=200mA
= −4V
= −40V
= −2V
= −10V
= −10V
25V
−0.01
1000
−0.1
Condition
100
−10
Fig.6 Collector-Emitter Saturation
10
−1
−0.001
−0.001
1
Ta=125°C
Ta=25°C
Ta= −40°C
Fig.3 DC Current Gain vs.
COLLECTOR CURRENT : I
Voltage vs. Collector Current
COLLECTOR CURRENT : I
I
I
−0.01
−0.01
C
C
/ I
/ I
B
B
Collector Current
=20 / 1
=10 / 1
∗1
∗1
∗1
∗2
−0.1
−0.1
2SA2094
−1
−1
V
Ta=25°C
CE
C
C
= −2V
(Ι)
(A)
(A)
2/3
(ΙΙ)
−10
−10