LT1495 Linear Technology, LT1495 Datasheet - Page 12

• Manufacturer Part Number: LT1495
• Description: 1.5uA Max/ Dual and Quad Precision Rail-to-Rail Input and Output Op Amps
• Manufacturer: Linear Technology

LT1495/LT1496
TYPICAL APPLICATIONS
12
RELATED PARTS
PART NUMBER
LTC1440/41/42
LTC1443/44/45
LT1466/LT1467
LT1490/LT1491
LTC1540
LT2078/LT2079
LT2178/LT2179
e
in
V
I
ZEROS AT 50Hz AND 60Hz
S
215k
169k
1/2 LT1495
S
15nF
15nF
= 2 A + e
= 5V, 0V
Linear Technology Corporation
1630 McCarthy Blvd., Milpitas, CA 95035-7417 [phone]
FAX: [phone] TELEX: 499-3977 www.linear-tech.com
A2
DISCHARGE
+
–
6th Order 10Hz Elliptic Lowpass Filter
15nF
in
15nF
215k
169k
30nF
30nF
CHARGE
/150k
I
2N3904
L
DESCRIPTION
Micropower Single/Dual Comparators with 1% Reference
Micropower Quad Comparators with 1% Reference
75 A Dual/Quad Rail-to-Rail Input and Output Op Amps
50 A Dual/Quad Rail-to-Rail Input and Output Op Amps
Nanopower Single Comparator with 1% Reference
55 A Dual/Quad Single Supply Op Amps
17 A Dual/Quad Single Supply Op Amps
R
B
R
R
Battery Current Monitor
A
A
DISCHARGE
OUT
215k
169k
R
0.1
SENSE
80.6k
100k
CHARGE
100k
100k
100nF
100nF
OUT
R
R
2N3904
A
A
U
+
–
+
–
1/2 LT1495
1/2 LT1495
1/2 LT1495
R
B
–
1/2 LT1495
+
N
200k
10nF
200k
10nF
V
FOR R
V
I
A1
L
O
O
5V
= I
= 1V/A
1495 TA03
L
A
= 1k, R
R
R
B
A
R
SENSE
10k
10k
B
OUTPUT
1495 TA05
= 10k
12V
100nF
100nF
COMMENTS
LTC1440: Single, LTC1441/42: Dual
LTC1443: 1.182 Reference
LTC1444/45: 1.221V Reference and Adjustable Hysteresis
390 V V
950 V V
350nA Supply Current
120 V V
120 V V
CURRENT
INPUT
OS(MAX)
OS(MAX)
OS(MAX)
OS(MAX)
10k
R4
, Gain Bandwidth = 120kHz
, Gain Bandwidth = 200kHz
, Gain Bandwidth = 200kHz
, Gain Bandwidth = 60kHz
–10
–20
–30
–40
–50
–60
0
1
0nA to 200nA Current Meter
Filter Frequency Response
–
+
LT1495
1/2
100pF
10M
R1
10
FREQUENCY (Hz)
A
LINEAR TECHNOLOGY CORPORATION 1997
R2
9k
R3
2k
FULL-SCALE
ADJUST
0 A TO
200 A
14956f LT/TP 0697 5K • PRINTED IN USA
100
LT1495/96 • TA04
1495 TA06
I
NO ON/OFF SWITCH
REQUIRED
1.5V
1.5V
S
= 3 A WHEN I
1000
–
+
LT1495
1/2
IN
= 0