BZ054B223ZSBBQ AVX Corporation, BZ054B223ZSBBQ Datasheet - Page 21

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BZ054B223ZSBBQ

Manufacturer Part Number
BZ054B223ZSBBQ
Description
CAPACITOR SUPER, 0.0022F, 4.5V, 0.17OHM
Manufacturer
AVX Corporation
Series
BestCapr
Datasheet

Specifications of BZ054B223ZSBBQ

Capacitance Tolerance
+80, -20%
Voltage Rating
4.5VDC
Esr
0.17ohm
No. Of Pins
3
Capacitor Mounting
SMD
Operating Temperature Range
-20°C To +70°C
Capacitance
2200µF
Termination Type
Solder
Rohs Compliant
Yes
Filter Terminals
Solder
External Depth
2.1mm
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
BZ054B223ZSBBQ
Manufacturer:
TOKO
Quantity:
5 000
BestCap
High Power Pulse Supercapacitors
the battery alone. This increase in “talk time” is demonstrat-
ed in Figures 6(a) (Li-Ion at +25°C), and 6(b) (Li-Ion at 0°C).
PULSE CAPACITOR APPLICATIONS
As mentioned earlier, the voltage drop in a circuit is critical
as the circuit will not operate below a certain cut-off voltage.
There are two sources of voltage drop (∆V) which occur, the
first ∆V
(ESR) and the second, called the capacitive drop, is ∆V
From Ohm’s law,
Let us say that the instantaneous starting voltage is Vo, or
voltage for the circuit from where the voltage drops. If the
capacitor has an ESR of 100 milliOhms and the current is 1
amp,
On demand, during the discharge mode, the voltage V = Vo
- ∆V
20
∆V
ESR
ESR
= 1 amp x (0.100) ohms = 0.1 volts or 100 milli-volts.
ESR
= (Vo - 0.1) volts
3.5
2.5
3.5
2.5
is because of the equivalent series resistance
voltage = current x resistance or V = IR
4
3
2
4
3
2
0
0
GSM Pulse @ 2 Amps
Figure 6a. Li-ION Battery at +25°C
Figure 6b. Li-ION Battery at +0°C
Battery with Pulse Capacitor
Battery with Pulse Capacitor
100
100
Cutoff Voltage
3.4 Volts
3.5 Volts
3.6 Volts
Cutoff Voltage
3.4 Volts
3.5 Volts
3.6 Volts
®
200
Time (Minutes)
Time (Minutes)
Ultra-low ESR
200
GSM Pulse @ 2 Amps 0°C
% Increase
28%
100%
300%
% Increase
28%
73%
300%
300
Cutoff Voltage Limits
300
Battery Alone
Battery Alone
LI-ION Battery
400
500
400
C
.
The second voltage drop is because of the capacitance.
This is shown in the equation as a linear function because of
simplicity. Simply put,
Hence, ∆V
I x dt/C. This formula states that the larger the capacitance
value the lower the voltage drop. Compared to a Ta capacitor
this ∆V
BestCap
needed. If the current pulse itself is 1 amp, the current pulse
width is 1 second, and the capacitance is 10 millifarads, the
∆V
is out of the range of BestCap
becomes narrower, say 10 milli-seconds, and the capaci-
tance is 100 millifarads, the ∆V
= 0.1 volt or 100 milli-volts. This shows the advantage of the
large capacitance and hence the term “pulse” capacitor.
The specific power – specific energy graphs are used in the
battery industry to compare competitive products. As the dt
becomes smaller i.e.100 milliseconds, 10 milliseconds and
then 1 millisecond, our estimates show that the specific
power for the BestCap
competitors because of our choice of internal materials
chemistry.
Conclusion: we now clearly show that BestCap
advantage over competitors for short current pulse whose
widths are smaller than a few hundred milliseconds.
4.3 ENHANCING THE POWER CAPABILITY OF
PRIMARY BATTERIES
When electronic equipment is powered by a primary (non
rechargeable) battery, one of the limitations is the power
capability of the battery.
In order to increase the available current from the battery,
while maintaining a constant voltage drop across the battery
terminals, the designer must connect additional cells in
parallel leading to increased size and cost of both the
battery and the finished product.
When high power is only required for short periods more
sophisticated approaches can be considered. The tradition-
al approach involves using a high power rechargeable
battery, charged by a low power primary cell.
A far superior solution, however, is the use of a BestCap
Supercapacitor, which is a device specifically designed to
deliver high power.
Primary
Battery
C
The derivative, dQ/dt = I (current, in amps) = C x dV/dt
= 1A x 1Sec/0.01F, or a 100 volts; such an application
C
®
Q (charge) = C (capacitance) x V (voltage)
is reduced by a factor of about 10 to 100. So,
C
has an advantage where higher capacitance is
(dV, the voltage drop because of capacitance) =
Rechargeable
Battery
Traditional design:
®
is the highest as compared to our
®
C
. However, if the pulse width
= 1 x (10/1000)/(100/1000)
Equipment Requiring
High Current Pulses
Battery Powered
®
has an
®

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